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Difficulty:
95%
(hard)
Question Stats:
30% (01:48) correct
70%
(01:48)
wrong
based on 481
sessions
History
Date
Time
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Not Attempted Yet
Reggie was hiking on a 6-mile loop trail at a rate of 2 miles per hour. One hour into Reggie’s hike, Cassie started hiking from the same starting point on the loop trail at 3 miles per hour. What is the shortest time that Cassie could hike on the trail in order to meet up with Reggie?
(A) 0.8 hours
(B) 1.2 hours
(C) 2 hours
(D) 3 hours
(E) 5 hours
(A) 0.8 hours
(B) 1.2 hours
(C) 2 hours
(D) 3 hours
(E) 5 hours
So this question is from the MGMAT ROADMAP. I understand the first part of solution provided in it, that it will take cassie 2 hours to catch up to Regan. However, the solution also calculates time if cassie would do the hike in the opposite direction. Now this is really confusing to me. There is no methodology that I take from it that how Cassie is able to hike miles 6 miles in reverse while reggie is only able to hike 2 miles for that direction.
Answer is A.
Please help.
Answer is A.
Please help.
28 Jul 2016, 09:18
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Didn't get this (assumed they were both hiking in the same direction).
\(\text{speed} = \frac{\text{distance}}{\text{time}}\)
\(\text{distance travelled in 1 hour: }2 \text{ miles } (\text{speed} \times \text{time})\).
\(\text{Distance from }\color{red}{\text{end of the trail (anticlockwise)}}: 6 - 2 = 4 \text{ miles}\).
Speed that they are coming together: \(3mph + 2mph = 5mph\).
\(\text{Time} = \frac{\text{distance}}{\text{speed}} = \frac{4}{5} = 0.8\)
\(\text{speed} = \frac{\text{distance}}{\text{time}}\)
\(\text{distance travelled in 1 hour: }2 \text{ miles } (\text{speed} \times \text{time})\).
\(\text{Distance from }\color{red}{\text{end of the trail (anticlockwise)}}: 6 - 2 = 4 \text{ miles}\).
Speed that they are coming together: \(3mph + 2mph = 5mph\).
\(\text{Time} = \frac{\text{distance}}{\text{speed}} = \frac{4}{5} = 0.8\)
General Discussion
29 Jul 2016, 02:00
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DAllison2016
we don't need to assume here the direction.we need to find which will take less time
so there are 2 cases
1)both moving in same direction...then time would be 2 hrs
2)both moving in opp direction then time would be 0.8 hrs
as we need the shortest time it would be the second case
