GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 16 Sep 2019, 21:35 ### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. ### Request Expert Reply # Rick can solve x algebra problems per minute. Matt can solve y calculu

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Math Expert V
Joined: 02 Sep 2009
Posts: 57999
Rick can solve x algebra problems per minute. Matt can solve y calculu  [#permalink]

### Show Tags

1
4 00:00

Difficulty:   55% (hard)

Question Stats: 63% (01:54) correct 37% (01:35) wrong based on 304 sessions

### HideShow timer Statistics

Rick can solve x algebra problems per minute. Matt can solve y calculus problems per minute. If y is not equal to zero, is x/y > 3?

(1) x > 3
(2) –(x/y) < 3

Kudos for a correct solution.

_________________
Manager  Joined: 14 Sep 2014
Posts: 106
Concentration: Technology, Finance
WE: Analyst (Other)
Re: Rick can solve x algebra problems per minute. Matt can solve y calculu  [#permalink]

### Show Tags

1
Statement 1: x > 3 does not give any information on y and x could be an infinite number of values
Statement 2: dividing by a negative value in an inequality reverses the sign so if we divide both sides of the inequality by -1 then -(x/y) < 3 becomes (x/y) > 3 which is sufficient to answer the question.

The correct answer is B.
Manager  B
Joined: 27 May 2014
Posts: 79
Re: Rick can solve x algebra problems per minute. Matt can solve y calculu  [#permalink]

### Show Tags

2
Doesn't it become x/y>-3?
Director  G
Joined: 23 Jan 2013
Posts: 530
Schools: Cambridge'16
Re: Rick can solve x algebra problems per minute. Matt can solve y calculu  [#permalink]

### Show Tags

1
R=x/min, so x>=0 and integer
M=y/min, so y>0 and integer
Question: Is x/y>3 or x more than three times more than y? Yes/No question

St.1. x>0. No information about y. INSUFF

St.2. -(x/y)<3 => x/y>-3 means that x/y can be 0,1,2,3 or >3. INSUFF

St.1+St.2. Just exclude x/y=0 but still makes 1,2,3 or >3 possible. INSUFF

E
Manager  Joined: 27 Oct 2013
Posts: 200
Location: India
Concentration: General Management, Technology
GMAT Date: 03-02-2015
GPA: 3.88
Re: Rick can solve x algebra problems per minute. Matt can solve y calculu  [#permalink]

### Show Tags

1
Here we go:

y is not equal to zero (given)

St1: x > 3

No information is given for Y.

Clearly Insufficient.

St2: –(x/y) < 3

x/y > -3

x = 1, y = 1 (x/y > -3, but x/y is not > 3)

x = 8, y = 2 (x/y > -3, and x/y > 3)

Two solutions possible..
Clearly Insufficient.

Combining

We are talking in terms of efficiency of X and Y.

Take x = 4 and Y = 3 (x/y is not > 3)
Take x = 4 and Y = 1 (x/y > 3)

Two possible solutions.

Clearly E is the answer.
EMPOWERgmat Instructor V
Status: GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 15009
Location: United States (CA)
GMAT 1: 800 Q51 V49 GRE 1: Q170 V170 Re: Rick can solve x algebra problems per minute. Matt can solve y calculu  [#permalink]

### Show Tags

4
Hi All,

Certain DS questions on the Official GMAT will include a "redundant" piece of information in one (or both) of the two Facts. By 'redundant', I mean that it is information that was either already given in the prompt (or something that you can deduce from the information in the prompt). Redundant Facts are always insufficient (since you already had the information, the Fact does not offer anything new).

Here, we're told that Rick can solve X problems per minute and Matt can solve Y problems per minute. Neither of these 2 variables can be negative (a person cannot solve "negative" problems in the context of this question). We're also told that Y CANNOT be 0. As such, X/Y is either 0 or it's positive, so the information that -(X/Y) < 3 is redundant, since -(X/Y) is either 0 or it's negative and ALL of those possibilities are LESS than +3. Thus, Fact 2 is INSUFFICIENT.

While redundant information isn't that common on the Official GMAT, you'll likely have to deal with it at least once, so it's important to take the proper notes and make whatever deductions you can with the information that appears in the prompt.

GMAT assassins aren't born, they're made,
Rich
_________________
760+: Learn What GMAT Assassins Do to Score at the Highest Levels
Contact Rich at: Rich.C@empowergmat.com

*****Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!*****

# Rich Cohen

Co-Founder & GMAT Assassin Follow
Special Offer: Save \$75 + GMAT Club Tests Free
Official GMAT Exam Packs + 70 Pt. Improvement Guarantee
www.empowergmat.com/
Math Expert V
Joined: 02 Aug 2009
Posts: 7814
Re: Rick can solve x algebra problems per minute. Matt can solve y calculu  [#permalink]

### Show Tags

EMPOWERgmatRichC wrote:
Hi All,

Certain DS questions on the Official GMAT will include a "redundant" piece of information in one (or both) of the two Facts. By 'redundant', I mean that it is information that was either already given in the prompt (or something that you can deduce from the information in the prompt). Redundant Facts are always insufficient (since you already had the information, the Fact does not offer anything new).

Here, we're told that Rick can solve X problems per minute and Matt can solve Y problems per minute. Neither of these 2 variables can be negative (a person cannot solve "negative" problems in the context of this question). We're also told that Y CANNOT be 0. As such, X/Y is either 0 or it's positive, so the information that -(X/Y) < 3 is redundant, since -(X/Y) is either 0 or it's negative and ALL of those possibilities are LESS than +3. Thus, Fact 2 is INSUFFICIENT.

While redundant information isn't that common on the Official GMAT, you'll likely have to deal with it at least once, so it's important to take the proper notes and make whatever deductions you can with the information that appears in the prompt.

GMAT assassins aren't born, they're made,
Rich

hi empower ,
u are right that many times, there are redundant information...
But not in this case. Its very importantto read finer point between the lines..
it gives the speed as problems per minute.. now either a problem is solved or not solved, we cannot have a half solved problem..
this does mean that x and y are integers....
this is what i feel, although it may be possible the Q was not meant that way..
_________________
EMPOWERgmat Instructor V
Status: GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 15009
Location: United States (CA)
GMAT 1: 800 Q51 V49 GRE 1: Q170 V170 Re: Rick can solve x algebra problems per minute. Matt can solve y calculu  [#permalink]

### Show Tags

1
chetan2u wrote:
EMPOWERgmatRichC wrote:
Hi All,

Certain DS questions on the Official GMAT will include a "redundant" piece of information in one (or both) of the two Facts. By 'redundant', I mean that it is information that was either already given in the prompt (or something that you can deduce from the information in the prompt). Redundant Facts are always insufficient (since you already had the information, the Fact does not offer anything new).

Here, we're told that Rick can solve X problems per minute and Matt can solve Y problems per minute. Neither of these 2 variables can be negative (a person cannot solve "negative" problems in the context of this question). We're also told that Y CANNOT be 0. As such, X/Y is either 0 or it's positive, so the information that -(X/Y) < 3 is redundant, since -(X/Y) is either 0 or it's negative and ALL of those possibilities are LESS than +3. Thus, Fact 2 is INSUFFICIENT.

While redundant information isn't that common on the Official GMAT, you'll likely have to deal with it at least once, so it's important to take the proper notes and make whatever deductions you can with the information that appears in the prompt.

GMAT assassins aren't born, they're made,
Rich

hi empower ,
u are right that many times, there are redundant information...
But not in this case. Its very importantto read finer point between the lines..
it gives the speed as problems per minute.. now either a problem is solved or not solved, we cannot have a half solved problem..
this does mean that x and y are integers....
this is what i feel, although it may be possible the Q was not meant that way..

Hi chetan2u,

If you reread my post, you'll see that I made no reference to whether X and Y were integers or not (that point is irrelevant), only that X/Y had to be 0 or positive. As such -(X/Y) will EITHER be 0 or a negative value, so -(X/Y) will ALWAYS be less than 3, regardless of the values.

GMAT assassins aren't born, they're made,
Rich
_________________
760+: Learn What GMAT Assassins Do to Score at the Highest Levels
Contact Rich at: Rich.C@empowergmat.com

*****Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!*****

# Rich Cohen

Co-Founder & GMAT Assassin Follow
Special Offer: Save \$75 + GMAT Club Tests Free
Official GMAT Exam Packs + 70 Pt. Improvement Guarantee
www.empowergmat.com/
Math Expert V
Joined: 02 Aug 2009
Posts: 7814
Re: Rick can solve x algebra problems per minute. Matt can solve y calculu  [#permalink]

### Show Tags

EMPOWERgmatRichC wrote:
chetan2u wrote:

hi empower ,
u are right that many times, there are redundant information...
But not in this case. Its very importantto read finer point between the lines..
it gives the speed as problems per minute.. now either a problem is solved or not solved, we cannot have a half solved problem..
this does mean that x and y are integers....
this is what i feel, although it may be possible the Q was not meant that way..

Hi chetan2u,

If you reread my post, you'll see that I made no reference to whether X and Y were integers or not (that point is irrelevant), only that X/Y had to be 0 or positive. As such -(X/Y) will EITHER be 0 or a negative value, so -(X/Y) will ALWAYS be less than 3, regardless of the values.

GMAT assassins aren't born, they're made,
Rich

hi rich...
you may not have meant it, so it's perfectly fine. but my point is in general that even a sentence such as 'Rick can solve x algebra problems per minute. Matt can solve y calculus problems per minute'. can give us a point to move on... but as you say it was statement two which is renundant. this too may not be correct as the Q says x/y>3 and statement 2 when simplified tells us x/y>-3.. two different things..
i think i actually require to read Q again .. but kudos to you...
_________________
Manager  Joined: 14 Sep 2014
Posts: 106
Concentration: Technology, Finance
WE: Analyst (Other)
Re: Rick can solve x algebra problems per minute. Matt can solve y calculu  [#permalink]

### Show Tags

bankerboy30 wrote:
Doesn't it become x/y>-3?

Yes, you're right.
Math Expert V
Joined: 02 Sep 2009
Posts: 57999
Re: Rick can solve x algebra problems per minute. Matt can solve y calculu  [#permalink]

### Show Tags

Bunuel wrote:
Rick can solve x algebra problems per minute. Matt can solve y calculus problems per minute. If y is not equal to zero, is x/y > 3?

(1) x > 3
(2) –(x/y) < 3

Kudos for a correct solution.

VERITAS PREP OFFICIAL SOLUTION:

Solution: E

Statement (1) only tells us about x; INSUFFICIENT. Statement (2) can be rewritten as (-x)/y < 3. Y cannot be negative – no one does “negative” calculus problems per minute – so it must be positive. This means that we can multiply both sides by y knowing that the sign won’t flip, so –x < 3y. Multiplying both sides by -1 gives us x > -3y, and dividing by y gives us x/y > -3; INSUFFICIENT. Combined the statements are still insufficient: we could have x/y = 5/1, as that’s greater than -3, and we could have x/y = 4/3, as that’s also greater than -3. (E).
_________________
Board of Directors P
Joined: 17 Jul 2014
Posts: 2523
Location: United States (IL)
Concentration: Finance, Economics
GMAT 1: 650 Q49 V30 GPA: 3.92
WE: General Management (Transportation)
Re: Rick can solve x algebra problems per minute. Matt can solve y calculu  [#permalink]

### Show Tags

Bunuel wrote:
Rick can solve x algebra problems per minute. Matt can solve y calculus problems per minute. If y is not equal to zero, is x/y > 3?

(1) x > 3
(2) –(x/y) < 3

Kudos for a correct solution.

xexe...this one wants to trick you to pick B...
1 clearly insufficient.
2 multiply both sides by -1, and flip the inequality sign: x/y > -3 - not sufficient

1+2
x=4, y=2, nope
x=4, y=1, yes

1+2 not sufficient.

_________________
Current Student Joined: 12 Oct 2015
Posts: 3
Re: Rick can solve x algebra problems per minute. Matt can solve y calculu  [#permalink]

### Show Tags

S#1: x > 3
Mentioned about only x, so not sufficient

S#2:
–(x/y) < 3
x/y > -3 [flipped the inequality sign as multiplied by '-']

'> -3' only gives the starting range of the possible values that x/y can have, so we can come up with different values of x/y
case 1: x/y = 5, which satisfies x/y > -3, giving us YES for x/y >3
case 2: x/y = 2, which satisfies x/y > -3, giving us NO for x/y > 3
Therefore, not sufficient

S#1 + S#2:
x > 3 and x/y > -3
These give only the starting range of the possible values x/y can have, so we can come up with different values of x/y

case 1: x/y = 15/3 = 5, which satisfies x>3 and x/y > -3, giving us YES for x/y >3
case 2: x/y = 4/2 = 2, which satisfies x>3 and x/y > -3, giving us NO for x/y > 3

Therefore, not sufficient. Answer E.
Senior Manager  G
Status: Countdown Begins...
Joined: 03 Jul 2016
Posts: 279
Location: India
Concentration: Technology, Strategy
Schools: IIMB
GMAT 1: 580 Q48 V22 GPA: 3.7
WE: Information Technology (Consulting)
Re: Rick can solve x algebra problems per minute. Matt can solve y calculu  [#permalink]

### Show Tags

IMO: E

Statement 1 : clearly insufficient.
Statement 2 : Since we know that x and y are rates. They can not be negative.
(x/y)>0
Hence -(x/y)<0.
So -(x/y)<3 is not useful.
Manager  S
Joined: 27 Aug 2016
Posts: 88
Location: India
Schools: HEC Montreal '21
GMAT 1: 670 Q47 V37 GPA: 3
WE: Engineering (Energy and Utilities)
Re: Rick can solve x algebra problems per minute. Matt can solve y calculu  [#permalink]

### Show Tags

sterling19 wrote:
Statement 1: x > 3 does not give any information on y and x could be an infinite number of values
Statement 2: dividing by a negative value in an inequality reverses the sign so if we divide both sides of the inequality by -1 then -(x/y) < 3 becomes (x/y) > 3 which is sufficient to answer the question.

The correct answer is B.

well...i guess we both made the same silly mistake-forgot to change the sign of "3"...arghhh.
Non-Human User Joined: 09 Sep 2013
Posts: 12343
Re: Rick can solve x algebra problems per minute. Matt can solve y calculu  [#permalink]

### Show Tags

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________ Re: Rick can solve x algebra problems per minute. Matt can solve y calculu   [#permalink] 25 Aug 2019, 12:12
Display posts from previous: Sort by

# Rick can solve x algebra problems per minute. Matt can solve y calculu

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne  