Bunuel
Robert and Timothy both left their respective homes at 1 PM. Robert walked till a lake that was between 2.5 kilometres and 3 kilometres from his home, inclusive, and returned home between 1:55 PM and 2:05 PM. If Timothy walked 5 kilometres more than Robert and returned to her home at 3 PM, which of the following statements must be true?
I. The walking speed of Timothy was greater than that of Robert
II. Robert’s walking speed was close to 3 kilometers per hour
III. Had Robert covered 5 more meters every 18 seconds, his walking speed would have been greater than Timothy’s
A. I only
B. II only
C. III only
D. I, II and III
E. None of the above
Solution:Notice that Robert walked between 2 x 2.5 = 5 km and 2 x 3 = 6 km in 55 minutes to 65 minutes.
If Robert walked 5 km in 65 minutes, his speed was roughly 4.61 km/h. If, on the other hand, Robert walked 6 km in 55 minutes, his speed was roughly 6.55 km/h. His actual speed could have been anything between 4.61 and 6.55 kilometers per hour.
Assume Robert walked 6 km in 55 minutes. Then, Timothy walked 6 + 5 = 11 km in 2 hours. Thus, the speed of Timothy was 11/2 = 5.5 km/h, which is less than 6.55. Thus, statement I is not necessarily true.
We found that Robert’s speed was between 4.61 and 6.55 km/h. Since the lower end of Robert’s speed was 50% more than 3 km/h and his actual speed was even more than that, statement II is false.
Finally, 5 more meters every 18 seconds is the same thing as 5 x 200 more meters in 18 x 200 = 3,600 seconds = 1 hour. Thus, 5 more meters in 18 seconds means 1,000 meters = 1 kilometer more distance traveled; thus the speed would have been exactly 1 km/h greater. Under this assumption, Robert’s speed was between 4.61 + 1 = 5.61 km/h and 6.55 + 1 = 7.55 km/h.
We found that the fastest Timothy could ever walk was if he walked 11 km in 2 hours; i.e. a speed of 5.5 km/h. We see that even if Timothy walked the fastest he could, he could not walk as fast as Robert’s slowest possible speed. Thus, statement III is true.
Answer: C