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How I solved this

To solve this question, we may have to list down the numbers of the set, till we can see a pattern which can help us count faster till the 97th integer.

The set:

Single digit numbers: 5 (only 1)
Double digit numbers:

-> 15,25,35,45 (4 numbers)
-> 50 to 59 (10 numbers)
-> 65, 75, 85, 95 (4 numbers)

Total -> 4+10+4 = 18 numbers.

At this point, a pattern can be seen.

From 1 to 100 numbers, we see a total of 18+1 = 19 numbers. More importantly, this pattern continues for the next block of 100 numbers (100 to 199, 200 to 299, etc.)

So,
1 to 99 -> 19 numbers
100 to 199 -> 19 numbers (105, 115, 125, 135, 145, 150 to 159, 165, 175, 185, 195)

The closest we can get to the 97th integer in blocks of 19 numbers is till the 95th integer (19 x 5).

i.e.,
till 99 -> 19 numbers
100 to 199 -> 19 numbers
200 to 299 -> 19 numbers
300 to 399 -> 19 numbers
400 to 499 -> 19 numbers

The 95th integer in this set is therefore 495 (the last number of the 19-number block from 400 to 499).

95th integer -> 495
96th integer -> 500
97th integer -> 501 (choice C).

Harsha
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