Last visit was: 26 Apr 2026, 04:02 It is currently 26 Apr 2026, 04:02
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 26 Apr 2026
Posts: 109,832
Own Kudos:
811,327
 [1]
Given Kudos: 105,889
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,832
Kudos: 811,327
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 26 Apr 2026
Posts: 109,832
Own Kudos:
Given Kudos: 105,889
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,832
Kudos: 811,327
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
bhatiavai
Joined: 07 Dec 2009
Last visit: 28 Aug 2018
Posts: 66
Own Kudos:
112
 [1]
Given Kudos: 375
GMAT Date: 12-03-2014
Posts: 66
Kudos: 112
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
Mrinob
Joined: 05 Aug 2016
Last visit: 06 Dec 2017
Posts: 38
Own Kudos:
18
 [1]
Products:
Posts: 38
Kudos: 18
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
2003 :1000
2004 : {(100-x )/100}*1000=(100-x)*10
2005 : {(100+y )/100}*(100-x)*10

In 2005, unknown contains terms y-x-xy/100
Therefore, option B is sufficient
avatar
abhishek03050
Joined: 01 Sep 2016
Last visit: 05 Aug 2018
Posts: 29
Own Kudos:
Given Kudos: 93
Posts: 29
Kudos: 39
Kudos
Add Kudos
Bookmarks
Bookmark this Post
tough one.not sure if I can complete this during the test :?

Bunuel
Official Solution:


We need to determine the number of incidents reported in 2005. The problem tells us that 1,000 incidents were reported in 2003. In 2004, \(x\) percent fewer incidents were reported, so \((100 - x) \times 1,000\) incidents were reported. Since a percentage is equivalent to a fraction with a denominator of 100, we can express the number of incidents reported in 2004 as \(\frac{100 - x}{100} \times 1,000\). In 2005, \(y\) percent more incidents were reported than in 2004. This can be expressed as \(\frac{100 + y}{100}(\frac{100 - x}{100} \times 1,000)\). It is this target expression that we must find a value for.

Multiply the numerators and denominators: \(\frac{100 + y}{100}(\frac{100 - x}{100} \times 1,000) = \frac{1,000(100 + y )(100 - x)}{10,000}\).

Cancel 1,000 from the numerator and denominator and FOIL what remains: \(\frac{(100 + y)(100 - x)}{10} = \frac{10,000 - 100x + 100y - xy}{10}\).

Evaluating this expression will require either solving for \(x\) and \(y\) or finding a way to substitute a number for all variable terms.

Statement 1 says that \(xy = 50\). This does not allow us to solve for either \(x\) or \(y\). We can substitute it into our target expression to get \(\frac{10,000 - 100x + 100y - 50}{10}\), but doing so does not eliminate the need to solve for \(x\) and \(y\). Statement 1 is NOT sufficient to answer the question. Eliminate answer choices A and D. The correct answer choice is B, C, or E.

Statement 2 says that \(y - x - \frac{xy}{100} = 4.5\). Note that this equation has an \(x\) term, a \(y\) term, and a term containing \(xy\). Thus, substitution will likely be possible.

Divide the original expression by \(10\) to eliminate the fraction: \(\frac{10,000 - 100x + 100y - xy}{10} = 1,000 - 10x + 10y - \frac{xy}{10}\).

Now factor out an additional \(10\) and reorder the terms in the expression: \(10(100 + y - x - \frac{xy}{100})\).

The left side of the equation in statement 2 is contained in this expression. Thus, we know that we can find a value for the expression. Statement 2 alone provides sufficient information to answer the question.


Answer: B
avatar
fandango
Joined: 11 Oct 2016
Last visit: 18 Sep 2017
Posts: 19
Own Kudos:
Location: Russian Federation
GMAT 1: 740 Q47 V44
GPA: 3.5
GMAT 1: 740 Q47 V44
Posts: 19
Kudos: 3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
bhatiavai
hi Bunuel,

How would one attempt the question within 2 mins. even though I got the answer It took me 4 complete minutes!!

Thanks

It's an old post but since i've been solving this now, maybe it will help someone...

You can solve it within 2 minutes by getting the expression 1000 (100-x)(100+y) which is 1000 (10000+100y-100x-xy) and noticing that statement 2 has the same variables in the same order with the same signs: y - x - xy/100. I think you don't need to go any further - you can already see that it has a solution.
avatar
buan15
Joined: 14 Jun 2016
Last visit: 06 Jan 2022
Posts: 110
Own Kudos:
Given Kudos: 54
Location: India
GMAT 1: 610 Q49 V24
GMAT 2: 690 Q49 V33
WE:Engineering (Manufacturing)
Products:
GMAT 2: 690 Q49 V33
Posts: 110
Kudos: 238
Kudos
Add Kudos
Bookmarks
Bookmark this Post
fandango
bhatiavai
hi Bunuel,

How would one attempt the question within 2 mins. even though I got the answer It took me 4 complete minutes!!

Thanks

It's an old post but since i've been solving this now, maybe it will help someone...

You can solve it within 2 minutes by getting the expression 1000 (100-x)(100+y) which is 1000 (10000+100y-100x-xy) and noticing that statement 2 has the same variables in the same order with the same signs: y - x - xy/100. I think you don't need to go any further - you can already see that it has a solution.

We can use the formula for successive increase of x%, followed by decrease of y% is given by effective increase = x-y-xy/100.
Hence we can estimate the ultimate value without much of calculation. Final value= Intial Value* effective increase in %
avatar
karnikabansal
Joined: 24 Jul 2017
Last visit: 27 Oct 2018
Posts: 4
Own Kudos:
Given Kudos: 42
Posts: 4
Kudos: 1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi Bunuel,

I solved this question in under 1:30 minutes, by:
declaring (i) INSUFFICIENT - as only the value of xy is given, and by no means we can identify the separate values of x and y to find out the final value post the successive change.
(ii) SUFFICIENT - just by looking at it, since the direct formula of Successive change is given with its value.

My question is, was my decision to declare (i) insufficient too hasty ? And was my reasoning to it, correct ?


Please help.
avatar
temlon
Joined: 26 Apr 2018
Last visit: 10 May 2018
Posts: 4
Given Kudos: 2
Posts: 4
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
In my opinion you basically have to know that the formula for successive percentage change looks like Statement 2 because for me it would be hard to do the Math behind it in 2 min.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 26 Apr 2026
Posts: 109,832
Own Kudos:
Given Kudos: 105,889
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,832
Kudos: 811,327
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
The workers at a large construction company reported \(x\) percent fewer safety incidents in 2004 than in 2003, and \(y\) percent more incidents in 2005 than in 2004. If the workers reported a total of 1,000 incidents in 2003, how many incidents did the workers report in 2005?


(1) \(xy = 50\)

(2) \(y - x - \frac{xy}{100} = 4.5\)

The workers at a large construction company reported x percent fewer safety incidents in 2004 than in 2003, and y percent more incidents in 2005 than in 2004. If the workers reported a total of 1,000 incidents in 2003, how many incidents did the workers report in 2005?

The total # of incident is 2003 was 1,000;
The total # of incident in 2004 was x percent fewer than in 2003, so in 2004 there were \(1,000*(1-\frac{x}{100})\) incidents;
The total # of incident in 2005 was y percent more than in 2004, so in 2005 there were \(1,000*(1-\frac{x}{100})*(1+\frac{y}{100})=1,000(1+\frac{y}{100}-\frac{x}{100}-\frac{xy}{100*100)}=1,000(1+\frac{1}{100}(y-x-\frac{xy}{100}))\) incidents.

So, as you can see we need to find the value of \(y-x-\frac{xy}{100}\).

(1) xy=50. Not sufficient to find the required value.

(2) y-x-xy/100=4.5 --> we are directly given the value of \(y-x-\frac{xy}{100}\). Sufficient.

Answer: B.
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,986
Own Kudos:
Posts: 38,986
Kudos: 1,118
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderator:
Math Expert
109832 posts