It is currently 19 Nov 2017, 04:10

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Sarah operated her lemonade stand Monday through

Author Message
TAGS:

### Hide Tags

Manager
Joined: 11 Aug 2012
Posts: 124

Kudos [?]: 135 [0], given: 16

Schools: HBS '16, Stanford '16

### Show Tags

28 Dec 2012, 09:19
5
This post was
BOOKMARKED
00:00

Difficulty:

95% (hard)

Question Stats:

50% (03:27) correct 50% (03:39) wrong based on 226 sessions

### HideShow timer Statistics

Sarah operated her lemonade stand Monday through Friday over a two week period and made a total profit of 276 dollars. On hot days she sold cups of lemonade for a price that was 25 percent higher than the regular days. Each cup she sold had a total cost of 75 cents and Sarah did not incur any other costs. If every day she sold exactly 32 cups and 3 of the days were hot, then what was the price of 1 cup on a hot day?

A. $1.50 B.$ 1.88
C. $2.25 D.$ 2.50
E. $3.25 The question is easy; I already solved it. However, it takes time to do it and many steps. Do you know a method to solve it in less tan 1.75 minutes? [Reveal] Spoiler: OA Kudos [?]: 135 [0], given: 16 Intern Joined: 05 Jun 2012 Posts: 24 Kudos [?]: 13 [0], given: 0 WE: Marketing (Retail) Re: Sarah operated her lemonade stand Monday through [#permalink] ### Show Tags 29 Dec 2012, 03:20 danzig wrote: Sarah operated her lemonade stand Monday through Friday over a two week period and made a total profit of 276 dollars. On hot days she sold cups of lemonade for a price that was 25 percent higher than the regular days. Each cup she sold had a total cost of 75 cents and Sarah did not incur any other costs. If every day she sold exactly 32 cups and 3 of the days were hot, then what was the price of 1 cup on a hot day? A.$ 1.50
B. $1.88 C.$ 2.25
D. $2.50 E.$ 3.25

The question is easy; I already solved it. However, it takes time to do it and many steps. Do you know a method to solve it in less tan 1.75 minutes?

The steps are time taking , thought the calculations are easy..It took me also close to 2 minutes

Kudos [?]: 13 [0], given: 0

Intern
Joined: 27 Dec 2012
Posts: 14

Kudos [?]: 1 [0], given: 2

### Show Tags

28 May 2013, 10:02
Ok I am not getting the answer ... 1.50 .. How many days are you cobsidering 10 or 13 ?

Posted from GMAT ToolKit

Kudos [?]: 1 [0], given: 2

Math Expert
Joined: 02 Sep 2009
Posts: 42246

Kudos [?]: 132652 [3], given: 12331

### Show Tags

28 May 2013, 10:31
3
KUDOS
Expert's post
1
This post was
BOOKMARKED
Asishp wrote:
Ok I am not getting the answer ... 1.50 .. How many days are you cobsidering 10 or 13 ?

Posted from GMAT ToolKit

Sarah operated the stand Monday through Friday (5 days) over a two week period, thus she operated the stand for total of 10 days.

Sarah operated her lemonade stand Monday through Friday over a two week period and made a total profit of 276 dollars. On hot days she sold cups of lemonade for a price that was 25 percent higher than the regular days. Each cup she sold had a total cost of 75 cents and Sarah did not incur any other costs. If every day she sold exactly 32 cups and 3 of the days were hot, then what was the price of 1 cup on a hot day?

A. $1.50 B.$ 1.88
C. $2.25 D.$ 2.50
E. $3.25 7 regular days --> sales = 7*32*x = 224x; 3 hot days --> sales = 3*32*(1.25x) = 120x; Total sales = 224x+120x = 344x. Total cost = 10*32*0.75 = 240. Profit = 344x - 240 = 276 --> x=1.5. 1.25x=~1.88. Answer: B. Hope it's clear. _________________ Kudos [?]: 132652 [3], given: 12331 Intern Joined: 27 Dec 2012 Posts: 14 Kudos [?]: 1 [1], given: 2 Re: Sarah operated her lemonade stand Monday through [#permalink] ### Show Tags 28 May 2013, 11:42 1 This post received KUDOS But the OA says A .. Is it wrong ? Posted from GMAT ToolKit Kudos [?]: 1 [1], given: 2 Math Expert Joined: 02 Sep 2009 Posts: 42246 Kudos [?]: 132652 [1], given: 12331 Re: Sarah operated her lemonade stand Monday through [#permalink] ### Show Tags 28 May 2013, 12:26 1 This post received KUDOS Expert's post Asishp wrote: But the OA says A .. Is it wrong ? Posted from GMAT ToolKit Yes, OA is B. Edited. _________________ Kudos [?]: 132652 [1], given: 12331 Intern Joined: 27 Dec 2012 Posts: 14 Kudos [?]: 1 [1], given: 2 Re: Sarah operated her lemonade stand Monday through [#permalink] ### Show Tags 28 May 2013, 12:31 1 This post received KUDOS Thanks ... I also got the same answer ... Posted from GMAT ToolKit Kudos [?]: 1 [1], given: 2 Intern Joined: 15 Dec 2007 Posts: 13 Kudos [?]: 28 [2], given: 138 Re: Sarah operated her lemonade stand Monday through [#permalink] ### Show Tags 03 Nov 2013, 07:50 2 This post received KUDOS You can put it all in one formula: 276 = (32*7*p+32*3*1.25*p) - 75*10*32 276 = (224p + 120p) - 24000 (thats in cents, or$240)
276+240 = 344p
1.5=p
p*1.25=~1.8

Kudos [?]: 28 [2], given: 138

Non-Human User
Joined: 09 Sep 2013
Posts: 15684

Kudos [?]: 282 [0], given: 0

### Show Tags

14 Jan 2015, 10:20
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Kudos [?]: 282 [0], given: 0

Manager
Joined: 03 Jan 2015
Posts: 68

Kudos [?]: 40 [0], given: 224

Concentration: Strategy, Marketing
WE: Research (Pharmaceuticals and Biotech)

### Show Tags

15 Jan 2015, 20:43
Bunuel wrote:
Asishp wrote:
Ok I am not getting the answer ... 1.50 .. How many days are you cobsidering 10 or 13 ?

Posted from GMAT ToolKit

Sarah operated the stand Monday through Friday (5 days) over a two week period, thus she operated the stand for total of 10 days.

Sarah operated her lemonade stand Monday through Friday over a two week period and made a total profit of 276 dollars. On hot days she sold cups of lemonade for a price that was 25 percent higher than the regular days. Each cup she sold had a total cost of 75 cents and Sarah did not incur any other costs. If every day she sold exactly 32 cups and 3 of the days were hot, then what was the price of 1 cup on a hot day?

A. $1.50 B.$ 1.88
C. $2.25 D.$ 2.50
E. $3.25 7 regular days --> sales = 7*32*x = 224x; 3 hot days --> sales = 3*32*(1.25x) = 120x; Total sales = 224x+120x = 344x. Total cost = 10*32*0.75 = 240. Profit = 344x - 240 = 276 --> x=1.5. 1.25x=~1.88. Answer: B. Hope it's clear. Hi, Is there a quick way to calculate the following without a calculator: (516/344)*1.25 TO Kudos [?]: 40 [0], given: 224 Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 7736 Kudos [?]: 17790 [1], given: 235 Location: Pune, India Re: Sarah operated her lemonade stand Monday through [#permalink] ### Show Tags 16 Jan 2015, 00:08 1 This post received KUDOS Expert's post thorinoakenshield wrote: Hi, Is there a quick way to calculate the following without a calculator: (516/344)*1.25 TO $$\frac{516}{344} * \frac{5}{4}$$ 516 is divisible by 4 so cancel it out with 4 in the denominator: $$\frac{129}{344} * 5$$ Even now, the numbers are big. Try to see if you have any other common factors: 129 = 3 * 43 We see that 3 is not a factor of 344 (since 3+4+4= 11 which is not a factor of 3). Next check if 43 is a factor of 344. Note that 43*8 = 344 - brilliant! The numbers have reduced to $$\frac{3}{8} * 5 = \frac{15}{8}$$ _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

Veritas Prep Reviews

Kudos [?]: 17790 [1], given: 235

Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7736

Kudos [?]: 17790 [1], given: 235

Location: Pune, India

### Show Tags

16 Jan 2015, 01:18
1
KUDOS
Expert's post
1
This post was
BOOKMARKED
danzig wrote:
Sarah operated her lemonade stand Monday through Friday over a two week period and made a total profit of 276 dollars. On hot days she sold cups of lemonade for a price that was 25 percent higher than the regular days. Each cup she sold had a total cost of 75 cents and Sarah did not incur any other costs. If every day she sold exactly 32 cups and 3 of the days were hot, then what was the price of 1 cup on a hot day?

A. $1.50 B.$ 1.88
C. $2.25 D.$ 2.50
E. $3.25 The question is easy; I already solved it. However, it takes time to do it and many steps. Do you know a method to solve it in less tan 1.75 minutes? Total 10 days of sale - 3 hot, 7 regular Total cost price =$(3/4) * 32 cups * 10 days = $240 Total profit =$276
Total selling price = 240 + 276 = 516

Say, x is the selling price on regular day

516 = 7*x*32 + 3*(5x/4)*32 = Revenue on Regular day + Revenue on Hot day
516/32 = 7x + 15x/4
129/8 = 43x/4

129/2*43 = x

3/2 = x

Selling price on hot day = (5/4)*(3/2) = 15/8 = 1.88

_________________

Karishma
Veritas Prep | GMAT Instructor
My Blog

Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Kudos [?]: 17790 [1], given: 235 Senior Manager Status: DONE! Joined: 05 Sep 2016 Posts: 408 Kudos [?]: 25 [0], given: 283 Re: Sarah operated her lemonade stand Monday through [#permalink] ### Show Tags 27 Jan 2017, 15:43 Mon-Fri = 5 day work week Hot Days: PH = PR +0.25PR = 1.25PR Solution: = 3{32(1.25PR)}+2{32(PR)} =$276
--> PR = 276/184 = $1.5 --> PH = 1.25PR --> PH =$1.88

B.

Kudos [?]: 25 [0], given: 283

Director
Joined: 13 Mar 2017
Posts: 552

Kudos [?]: 134 [0], given: 64

Location: India
Concentration: General Management, Entrepreneurship
GPA: 3.8
WE: Engineering (Energy and Utilities)

### Show Tags

14 Aug 2017, 02:50
danzig wrote:
Sarah operated her lemonade stand Monday through Friday over a two week period and made a total profit of 276 dollars. On hot days she sold cups of lemonade for a price that was 25 percent higher than the regular days. Each cup she sold had a total cost of 75 cents and Sarah did not incur any other costs. If every day she sold exactly 32 cups and 3 of the days were hot, then what was the price of 1 cup on a hot day?

A. $1.50 B.$ 1.88
C. $2.25 D.$ 2.50
E. \$ 3.25

The question is easy; I already solved it. However, it takes time to do it and many steps. Do you know a method to solve it in less tan 1.75 minutes?

In the two week period, Sarah operated lemonade for total 10 days out of which 3 were hot days and 7 were regular days.
Let p be the selling price on regular day and 1.25 p be the selling price on hot days.

So, 32*1.25*p*3 +32*p * 7 - 32*10 *0.75 = 276
-> 32p(3.75 + 7) = 276 + 320*0.75 = 276 +240 = 516
-> p = 516/32/10.75 = 129/8*10.75= 129/86 = 3/2 = 1.5

So, price of 1 cup on hot day = 1.5 *1.25 ~ 1.88

_________________

MBA Social Network : WebMaggu

Appreciate by Clicking +1 Kudos ( Lets be more generous friends.)

Kudos [?]: 134 [0], given: 64

Re: Sarah operated her lemonade stand Monday through   [#permalink] 14 Aug 2017, 02:50
Display posts from previous: Sort by