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9 minutes = 9*60 = 540 seconds.

Seb’s watch gains 5 seconds in every 3 hours
Every hour Seb's match gain 5/3 seconds

Lewis’ watch loses 10 seconds in every 2 hours
Every hour Lewis’ watch loses 10/2 = 5 seconds

Relative difference per hour = 5 + 5/3 = 20/3 Seconds

Time taken to gain 540 seconds = 540/(20/3) = 540*3/20 = 81 hours

81 Hours = 72 Hours (3 24 Hour day) + 9 Hours =>

1 AM + 9 Hours = 10 AM, which is 3 days later i.e. Wednesday.

Option B
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Hello please help me out.is my approach correct.
3h=> 5sec increase,so
24h=> 40 sec increase.

Similarly 2h=> 10 sec decrease
24hr => 120 sec decrease
So for 48 hrs diff will be =150
72hrs difference will be =240
I am not getting answer like this,
Why this is wrong.

Posted from my mobile device
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harinageshwar
Hello please help me out.is my approach correct.
3h=> 5sec increase,so
24h=> 40 sec increase.

Similarly 2h=> 10 sec decrease
24hr => 120 sec decrease
So for 48 hrs diff will be =150
72hrs difference will be =240
I am not getting answer like this,
Why this is wrong.

Posted from my mobile device

You are wrong because you have assumed that both the increase and decrease are happening over a 2 days , wheras they're actually happening simultaneously.
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The point of this question is that recognizing the least common multiple, 6, simplifies the problem.

Every 6 hrs Seb's watch gains 10 seconds and Lewis's watch loses 30 seconds, for a total difference of:

40s/6 hrs

Since 9 minute difference = 540 seconds, the number of hours required to generate this difference is:

540s/(40s/6hrs) = 13.5*6 =

81 hours.

Since 72 hours = 3 days, 3 days and 9 hours must pass.

So, Wednesday at 10 am

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