duttsit
D.
In a right angle triangle, altitude divides original triangle into 2 similar traingles. By similar triagle property (ratio of sides same) we can get:
2 * 2 = a * b
knowing a or b will give the other and we can find a + b.
That's cool way of solving it duttsit! You rock!
I took a roundabout way but arrived there.
1) a =4, altitude = 2, angle = 90
SUFFICIENCY for a triangle,
All angles and 1 side known => rest of the sides can be determined
Two sides and included angle known => rest of the angles + other side can be determined
From (1), we can find angle QPR and angle angle QRP (since PQR = 90, angle inscribed in a Semi-Ole)
The smaller right angled triangle, knowing angle QRP, we are in a situation where 3 angles and one side (altitude =2) is known. Hence "b" can be found.
2) Same reasoning as #1, given b we can find a.