Set A consists of integers {3, -8, Y, 19, -6} and set B consists of in

Set A = {-8,-6,3,19} and Y
Set B = {-5,-3,0,9,16} and K

Now; Y>21. Let's consider Y=22.

This will make the median of Set A as 3.
Median = (n+1)/2 if n=number of terms in the set and n=odd
Here n=5. Median will be 6/2=3rd term of the set A arranged in ascending order.

Set A = {-8,-6,3,19,22}. Median = L = 3

\(Z=L^M\)
\(Z=3^M\)

We need to know what should M be for making Z a divisor of 26.

Since 26 contains only 2 and 13 as prime factors. The only option left for M is 0.
\(Z=3^M=3^0=1\)
Z=1 and is a factor of 26.

To make M=0; we need to have maximum number of 0's in the set B.
Since all of the elements are different in Set B. If we make K=0, we will have 2 0's and 0 will be the mode of the set.

Mode of Set B = {-5,-3,0,9,16,0} = 0

Ans: "C"