Last visit was: 19 Nov 2025, 11:40 It is currently 19 Nov 2025, 11:40
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
tejal777
Joined: 25 Oct 2008
Last visit: 09 Jan 2012
Posts: 360
Own Kudos:
Given Kudos: 100
Location: Kolkata,India
Posts: 360
Kudos: 6,912
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Jivana
Joined: 20 Mar 2008
Last visit: 26 Apr 2011
Posts: 339
Own Kudos:
Given Kudos: 5
Posts: 339
Kudos: 435
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
GMAT TIGER
Joined: 29 Aug 2007
Last visit: 17 Aug 2011
Posts: 1,013
Own Kudos:
Given Kudos: 19
Posts: 1,013
Kudos: 1,783
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
over2u
Joined: 09 Aug 2009
Last visit: 23 Aug 2020
Posts: 15
Own Kudos:
Given Kudos: 1
Posts: 15
Kudos: 19
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Mode - is the number what appears most. Basically it could be several modes in one set.
1) Let's consider the first statement.
We have the following set {3,3,5,7,7}. Mean and median are equal 5, and we have two modes 3 and 5, so insuf
2)Let's consider two sets. {1,1,4,6,8} and {1,3,4,6,6}
If the median will be removed from the first set, mean and mode will remain the same
If the median will be removed from the second set, mean and mode will change. Suff.
I choose B.
User avatar
tejal777
Joined: 25 Oct 2008
Last visit: 09 Jan 2012
Posts: 360
Own Kudos:
Given Kudos: 100
Location: Kolkata,India
Posts: 360
Kudos: 6,912
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Stmt 2 is the real gem here...

The main problem I had with this ques was the difficulty in coming up with examples of sets..any different approach or any pointers on how to do it under 2 mins??
User avatar
Jivana
Joined: 20 Mar 2008
Last visit: 26 Apr 2011
Posts: 339
Own Kudos:
Given Kudos: 5
Posts: 339
Kudos: 435
Kudos
Add Kudos
Bookmarks
Bookmark this Post
tejal777
Stmt 2 is the real gem here...

The main problem I had with this ques was the difficulty in coming up with examples of sets..any different approach or any pointers on how to do it under 2 mins??

The key to this problem is to figure out what happens if the mode is higher or lower than the median. Once you zero in on that, you are set.

This problem took me about 3 mins or so. Given that this is a difficult one, I wouldn't stress too much about trying to keep it under 2 mins. Remember, you are trying to solve every problem under 2 mins, on average. Some problems might take 2.5 and some might take 3 mins. But then again, you will have a few of the 30 sec ones, where you can average it out.
avatar
gmate2010
Joined: 25 Aug 2009
Last visit: 26 Nov 2009
Posts: 96
Own Kudos:
Given Kudos: 12
Posts: 96
Kudos: 251
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Jivana
tejal777
Set X is composed of the total daily rainfall for a 5 day period.Is the mode of set X greater than the median?
1. mean and median od set X is equal to 5
2. If the median was removed from set X,the mean and mode would remain unchanged,but the median would decrease.
1. Consider set {1,3,5,7,9} & {5,5,5,5,5}. The first one has no mode (mode is the number that appears the most.) The second one's mode, mean & median is 5. Insuff.

2. Consider set {0,2,5,9,9} , {1,1,5,8,10} & {3,3,5,6,8}.

Set1: All conditions satisfy, except the median decrease. median increase to 9+2 / 2 = 5.5.
Set2: All conditions satisfy. median = 4.5. Mode = 1 < median.
Set3: All conditions satisfy. median = 4.5. Mode = 3 < median.

Based on this, we can conclude, that mode will always be less than the median.

Suff.

B

I disagree with your definition of mode!!! In Case 1, all numbers appear only once, hence, all 5 numbers are mode here..
User avatar
Jivana
Joined: 20 Mar 2008
Last visit: 26 Apr 2011
Posts: 339
Own Kudos:
Given Kudos: 5
Posts: 339
Kudos: 435
Kudos
Add Kudos
Bookmarks
Bookmark this Post
gmate2010
Jivana
tejal777
Set X is composed of the total daily rainfall for a 5 day period.Is the mode of set X greater than the median?
1. mean and median od set X is equal to 5
2. If the median was removed from set X,the mean and mode would remain unchanged,but the median would decrease.
1. Consider set {1,3,5,7,9} & {5,5,5,5,5}. The first one has no mode (mode is the number that appears the most.) The second one's mode, mean & median is 5. Insuff.

2. Consider set {0,2,5,9,9} , {1,1,5,8,10} & {3,3,5,6,8}.

Set1: All conditions satisfy, except the median decrease. median increase to 9+2 / 2 = 5.5.
Set2: All conditions satisfy. median = 4.5. Mode = 1 < median.
Set3: All conditions satisfy. median = 4.5. Mode = 3 < median.

Based on this, we can conclude, that mode will always be less than the median.

Suff.

B

I disagree with your definition of mode!!! In Case 1, all numbers appear only once, hence, all 5 numbers are mode here..

No, that's not true. There can be multiple modes in a set, for example in the set {1,5,1,3,5,3,8,10} 1,3,5 are all modes. However, if all the numbers are unique then that set has no mode.
avatar
gmate2010
Joined: 25 Aug 2009
Last visit: 26 Nov 2009
Posts: 96
Own Kudos:
Given Kudos: 12
Posts: 96
Kudos: 251
Kudos
Add Kudos
Bookmarks
Bookmark this Post
if it is so, then it's a news for me ... :) :)
User avatar
Mikko
Joined: 25 Mar 2009
Last visit: 03 Oct 2010
Posts: 26
Own Kudos:
Given Kudos: 9
Posts: 26
Kudos: 38
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Tks alot

It's so difficult, I can understand the 2 explanations but I cant have that way of reasoning :(



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderators:
Math Expert
105390 posts
GMAT Tutor
1924 posts