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Seven different numbers are selected from the integers 1 to 100, and each number is divided by 7. What is the sum of the remainders?
(1) The range of the seven remainders is 6.
(2) The seven numbers selected are consecutive integers
(1) The range of the seven remainders is 6.
(2) The seven numbers selected are consecutive integers
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20 Oct 2004, 11:25
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I pick B.
1) Insufficient, since we don't know the numbers, some of the may have the same remainder.
2) Sufficient. Sum of remainders is always 21.
Examples:
1,2,3,4,5,6,7 => Sum of remainders=21.
6,7,8,9,10,11,12 => Sum of remainders=21.
1) Insufficient, since we don't know the numbers, some of the may have the same remainder.
2) Sufficient. Sum of remainders is always 21.
Examples:
1,2,3,4,5,6,7 => Sum of remainders=21.
6,7,8,9,10,11,12 => Sum of remainders=21.
22 Oct 2004, 15:53
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Hey guys, I think the answer is C
The questions states that each number is divided by 7.
So 1,2,3,4,5,6 divided by 7 does not give us remainders. Thats why I think B isnt sufficient.
With C, knowing from statement 1 that the remainders range from 0-6, the smallest number divisible by 7 is 7. So, 7,8,9,10,11,12,13 divided by 7 will all have remainders adding up to 21.
or 21,22,23,24,25,26,27 all will have remainders adding up to 21 when divided by 7.
The questions states that each number is divided by 7.
So 1,2,3,4,5,6 divided by 7 does not give us remainders. Thats why I think B isnt sufficient.
With C, knowing from statement 1 that the remainders range from 0-6, the smallest number divisible by 7 is 7. So, 7,8,9,10,11,12,13 divided by 7 will all have remainders adding up to 21.
or 21,22,23,24,25,26,27 all will have remainders adding up to 21 when divided by 7.
"B" it is.
