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Six friends go to see a comedy at the local movie theater and sit in a

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Six friends go to see a comedy at the local movie theater and sit in a  [#permalink]

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New post 08 Apr 2016, 01:43
1
5
00:00
A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

58% (01:28) correct 42% (01:53) wrong based on 139 sessions

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Six friends go to see a comedy at the local movie theater and sit in a particular row together. If Grady and Howard are among those 6 friends but can never sit next to each other, how many 6-person seating arrangements are possible?

A. 360
B. 420
C. 480
D. 600
E. 720

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Re: Six friends go to see a comedy at the local movie theater and sit in a  [#permalink]

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New post 08 Apr 2016, 07:03
1
Ways to arrange 6 people in a row = 6! = 720

From this we want to subtract all the arrangements where Grady and Howard are next to each other. If we consider Grady and Howard one unit (GH), then the number of arrangements of the GH unit and the 4 other friends is 5! And the number of arrangements of G and H within the GH unit are 2 (GH or HG). So the total number of arrangements of the 6 friends with Grady and Howard together are 5!*2

Number of permutations where Grady and Howard are not seated next to each other = 6! - 5!*2 = 720-120*2 = 480

Answer: C
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Re: Six friends go to see a comedy at the local movie theater and sit in a  [#permalink]

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New post 03 Jul 2016, 14:18
1
6 persons can be arranged in a row in 6! ways = 720 ways
consider Grady and Howard as 1 group in which they both sit together so we have 4 persons and 1 group
they can be arranged in 5! ways
Grady and Howard can arrange themselves in 2! ways
so in total the number of ways in which they are together is 5! * 2! = 120 * 2 = 240
subtract this number from total number of arrangements to get the number of arrangements in which Grady and Howard are not sitting together
720 - 240 = 480
Correct Answer - C
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Re: Six friends go to see a comedy at the local movie theater and sit in a  [#permalink]

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New post 24 Aug 2016, 19:04
Bunuel wrote:
Six friends go to see a comedy at the local movie theater and sit in a particular row together. If Grady and Howard are among those 6 friends but can never sit next to each other, how many 6-person seating arrangements are possible?

A. 360
B. 420
C. 480
D. 600
E. 720



If Gary sits on one of the two corners, then Hardy will have 4 options, So 2(Gary's 2 corner) * 4(Hardy's 4 position) * 4!, the remaining 4 can have 4! arrangement,
And if Gary sits other than the corner, then Hardy will have only 3 options, So that is 4 * 3 * 4!

In total 2 * 4 * 4! + 4 *3 * 4! = 480.

answer is C.



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Re: Six friends go to see a comedy at the local movie theater and sit in a  [#permalink]

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New post 17 Dec 2017, 12:13
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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Six friends go to see a comedy at the local movie theater and sit in a &nbs [#permalink] 17 Dec 2017, 12:13
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