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Six years ago Anita was P times as old as Ben was. If Anita is now 17

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Six years ago Anita was P times as old as Ben was. If Anita is now 17 [#permalink]

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New post 19 May 2016, 03:06
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Six years ago Anita was P times as old as Ben was. If Anita is now 17 years old, how old is Ben now in terms of P ?

A. 11/P + 6
B. P/11 +6
C. 17 - P/6
D. 17/P
E. 11.5P

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Re: Six years ago Anita was P times as old as Ben was. If Anita is now 17 [#permalink]

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New post 19 May 2016, 03:35
Bunuel wrote:
Six years ago Anita was P times as old as Ben was. If Anita is now 17 years old, how old is Ben now in terms of P ?

A. 11/P + 6
B. P/11 +6
C. 17 - P/6
D. 17/P
E. 11.5P


let's call Ben age six years ago is x

so six year age Anita was: 17-6 = 11 years old

and six years ago Anita was P times as old as Ben was
=> 11/x = P
=> x = 11/P
=> Now Ben age will be : x+6 = 11/P+6
=> the answer is A
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Re: Six years ago Anita was P times as old as Ben was. If Anita is now 17 [#permalink]

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New post 19 May 2016, 10:55
A-6= P(B-6)

A-6/P +6 = B

17-6/P +6= B
11/P +6 =B

A is the answer
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Six years ago Anita was P times as old as Ben was. If Anita is now 17 [#permalink]

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New post 20 May 2016, 08:38
Six years ago Anita was \(17-6 = 11\), Ben was \(B=A/P\) therefore\(B=11/P\)
Now six years have passed and\(B + 6 = 11/P + 6\) or \(Older Ben = \frac{11+6P}{P}\)
or as in the solutions A)
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Re: Six years ago Anita was P times as old as Ben was. If Anita is now 17 [#permalink]

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New post 14 Oct 2017, 11:08
If 4x is 6 less than 4y, then y – x =?

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Re: Six years ago Anita was P times as old as Ben was. If Anita is now 17   [#permalink] 14 Oct 2017, 11:08
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Six years ago Anita was P times as old as Ben was. If Anita is now 17

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