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Solution Y is 30 percent liquid X and 70 percent water. If 2

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Solution Y is 30 percent liquid X and 70 percent water. If 2 [#permalink]

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18 Jul 2004, 23:13
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Solution Y is 30 percent liquid X and 70 percent water. If 2 kilograms of water evaporate from 8 kilograms of solution Y and 2 kilograms of solution Y are added to the remaining 6 kilograms of liquid, what percent of this new solution is liquid X?

A. 30%
B. 33 1/3%
C. 37 1/2%
D. 40%
E. 50%

OPEN DISCUSSION OF THIS QUESTION IS HERE: solution-y-is-30-percent-liquid-x-and-70-percent-water-if-130321.html
[Reveal] Spoiler: OA

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19 Jul 2004, 01:31
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Y has 30% X and 70% of water
therefore 8kg of Y wd hv 2.4kg X and 5.6 of Water
if 2 kg of water evaporates, then water left is 3.6
2 kg of solution Y is added so it wd add 0.6 kg of X and 1.4 kg of water.
thus we have 3(2.4+0.6) kg of X in 8 kg(6+2 added) of solution Y which is 3/8 fraction or (3/8)*100% of solution X in the new mixture which comes to 37.5%
i cant think of any faster solution..if there is,please let me know friends
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19 Jul 2004, 07:41
I agree with viveksah and I might have done the same thing. But in general with mixture problems, I always make a quick chart that's designed to line everything up properly. In this case, the chart looked like this:

Note: The zero in the percent of water after the water evaporated is just a place holder, not a zero. I just didn't bother calculating it since it's not important.

From here, I can see that 5/8 of the new mixture are water, so 3/8 are liquid x. I chose to do the whole chart in water because water is what evaporated from the original.

whenever there's a mixture problem, there's always the whole, the percentage, and then the part. If you line it all up properly, and add down, the chart takes care of the rest.

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27 Jul 2004, 03:28
I came up with C, too.

The question is: what percent of this new solution is liquid X? That is the ratio of liquid x to solution y. So you only need to find out the eventual kilograms of liquid x and kilograms of solution y.
liquid x is consisted of two parts:
part 1: the original part ---- 30% x 8 kg
part 2: the added liquid x part ---- 30% x 2 kg
So the total of liquid x is 30% x 8 + 30% x 2 = 30% (8 + 2) = 3
The eventual solution y is 8 kg, which is very obvious, so you can write it this way:

(30% x 8 + 30% x 2) / 8 = 3/8 = 0.375

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19 Aug 2009, 20:55
Good explanation Ian.

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21 Aug 2009, 06:38
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OA C

Initial solution => 8 kg (x:w :: 2.4:5.6)
After evaporation Initial solution => 6 kg (x:w:: 2.4:3.6)

New solution => 2 kg (x:w::0.6:1.4)

Mixing (Initial solution + New solution) => 6 kg (2.4:3.6)+ 2 kg (0.6:1.4) =

= 8 kg [(2.4+0.6) : (3.6+1.4)]
= 8 kg (x : water :: 3kg : 5 kg)
Hence % of x = 3/8 = 37.5%.....OA C
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Re: Solution Y is 30 percent liquid X and 70 percent water. If 2 [#permalink]

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25 Nov 2013, 08:40
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Re: Solution Y is 30 percent liquid X and 70 percent water. If 2 [#permalink]

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25 Nov 2013, 08:47
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Expert's post
Solution Y is 30 percent liquid X and 70 percent water. If 2 kilograms of water evaporate from 8 kilograms of solution Y and 2 kilograms of solution Y are added to the remaining 6 kilograms of liquid, what percent of this new solution is liquid X?
A. 30%
B. 33 1/3%
C. 37 1/2%
D. 40%
E. 50%

In 8 kilograms of solution Y there are 0.3*8=2.4 kilograms of solution X;

After 2 kilograms of water are replaced by 2 kilograms of solution Y, to the existing 2.4 kilograms of solution X, 0.3*2=0.6 kilograms of solution X are added, so in the new solution of 8 kilograms there are 2.4+0.6=3 kilograms of solution X, which is 3/8*100=37.5% of this new solution.

OPEN DISCUSSION OF THIS QUESTION IS HERE: solution-y-is-30-percent-liquid-x-and-70-percent-water-if-130321.html
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Re: Solution Y is 30 percent liquid X and 70 percent water. If 2 [#permalink]

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18 Apr 2014, 21:37
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30%X | 70%W

Step 1: 2.4 X | 5.6 W

Step 2: 2.4 X | 3.6 W

Step 3: +0.6 X | + 1.4 W

Final: 3 X | 5 W

Proportion

3/8 * 100 = 75/2
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Re: Solution Y is 30 percent liquid X and 70 percent water. If 2   [#permalink] 18 Apr 2014, 21:37
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