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Bunuel
Square S is inscribed in circle T. If the perimeter of S is 24, what is the circumference of T?

A. 6π
B. 12π
C. 3√2*π
D. 6√2*π
E. 12√2*π

4s = 24

So, s = 6 ( Each side of the square is 6 )

Now, Diagonal of the Square = Diamter of the Circle

So, \(6\sqrt{2}\)= Diameter of the Circle

Now, Circumference of the Circle is π*Diamter of the Circle = 6√2*π , Answer must be (D)
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Bunuel
Square S is inscribed in circle T. If the perimeter of S is 24, what is the circumference of T?

A. 6π
B. 12π
C. 3√2*π
D. 6√2*π
E. 12√2*π

The square is inside the circle, see attachment below. Then the length of the square is longer than the radius of the circle. Radius = 6 / sqrt(2) = 3*sqrt(2), and the circumference is 2pi * 3sqrt(2). Thus the answer is D.
Attachments

square in circle.png
square in circle.png [ 38.18 KiB | Viewed 10419 times ]

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Bunuel
Square S is inscribed in circle T. If the perimeter of S is 24, what is the circumference of T?

A. 6π
B. 12π
C. 3√2*π
D. 6√2*π
E. 12√2*π

Since the perimeter of S is 24, each side is 6, and the diagonal of S = the diameter of T = 6√2. Thus, the circumference of T is 6√2*π.

Answer: D
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