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amitdgr


6. Calculation of Standard Deviation (SD):
i) Find the mean of the set of numbers
ii) Find the difference between each of the numbers and the mean
iii) Square the differences and add them together
iv) Take the positive square root of this value

Please add if i missed something.

Step iii) above is not quite right- you want to take the mean of the squares, not the sum.
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11. SD ranks the dispersion (deviation) of the numbers in a list. The more alike the numbers are, the less the dispersion, so the less the standard deviation

13. The more uneven members are dispersed around their arithmetic average, the more their SD

21. For data with approximately the same mean, the greater the range, the greater the SD

26. For odd number of consecutive integers median = mean

Please add if i missed something.

In 11: this could be confusing. A set such as {0,0,0,0, 1000000, 1000000, 1000000, 1000000} contains numbers which are very much 'alike' but the set has a huge standard deviation: all of its elements are very far from the mean.

In 13: I'm not exactly sure what you're trying to say here.

In 21: This is not a mathematical rule; indeed it's very often untrue. The set S = {100, 50, 50, 50, 50, 50, 50, 50, 0} has the same mean as the set T = {99, 99, 99, 99, 99, 99, 1, 1, 1, 1, 1, 1}, and has a larger range. It has a much smaller standard deviation, however.

In 26. For any number of consecutive integers, median = mean. You can remove the word 'odd'. Indeed, in any arithmetic progression, the median = mean.
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Thanks Ian .. I guess I mistook some of the concepts :)
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Thanks man. Into my book marks.
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Thanks very much for the effort....however, do we need this sort of stat knowledge for GMAT?
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Thanx for the this useful stuff!!!
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shortcut**

S.D=Sq.root(mean of the squares-square of the mean)
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Thank you so much amitdgr!!
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Good compilation .. Thanks dude
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amitdgr


so basically if I have the following numbers

112, 113, 114, 115, 116, 117
I dont need to do the sum/6
i basically can do 112+117/6
which gives me the mean and the median!!!

thank you soo much that saves lots of time especially with big numbers!!!

h.


Typo.........Should be divided by 2........
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Quote:
1.SD does not change when the same constant is added or subtracted to all the members of the set.
Could you explain how this verbatim would affect the below problem?

A certain list of 100 data has an average of 6 and standard deviation of d where d is positive. Which of the followig pairs of data, when added to the list must result in a ist of 102 data with the standard deviation less than d?

Answer choices -

1. 0 and 6
2. 0 and 12
3. 0 and 0
4. -6 and 0
5. 6 and 6

Thanks,
Vannu
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It is totally Ok. Welcome.
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Great post!

Just out of curiousity... has anyone actually seen a standard deviation problem in the real thing?
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Tip1.
Always keep in mind:
Range >= SD >=0

Case1: when the set of numbers given are +ve and different: 2 3 4 : Range = 2, SD = sq-root (2/3). R > SD
Case2: when the set of numbers given are -ve and different: -4 -3 -2 : Range = 2, SD = sq-root (2/3). R > SD
Case3: Only in case of all numbers are equal, then Range = SD = 0, already mentioned above.

There cud be a problem where you are asked to arrange the Mean, median, mode, range & SD, any of these in ascending order. or framed differently for DS questions.

Tip2:
Edit: Set of consecutive integers has mean 0, means set is symmetric about the origin. And yes # of terms should be odd. Thanks Bunuel
Case1: either all numbers are zero
Case2: or there are odd number of integers
Helpful for DS again.

Kudos if you like the tips. More to come.........

Edit: Thanks Bunuel, edited the post as advised by you
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ctrlaltdel

Tip2:
There is a formula: (I don't know if it will be relevant for GMAT)
3*Median = 2*Mode + Mean
Helpful for DS.

I think it's not true. If set is for example: {1,1,1,5,7}
Mean=3
Median=1
Mode=1

And equation doesn't hold true. Check the source.

ctrlaltdel
Tip3:
If the Mean of set of consecutive numbers is zero, then:
Case1: either all numbers are zero
Case2: or there are odd number of integers
Helpful for DS again.

If we have set of consecutive integers how can all numbers be zero?

Set of consecutive integers has mean 0, means set is symmetric about the origin. And yes # of terms should be odd.
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Edit: Sorry for the confusion :oops:
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https://www.pinkmonkey.com/studyguides/subjects/stats/chap4/s0404601.asp

4.6 Empirical Relation Between Mean, Median And Mode

A distribution in which the values of mean, median and mode coincide (i.e. mean = median = mode) is known as a symmetrical distribution. Conversely, when values of mean, median and mode are not equal the distribution is known as asymmetrical or skewed distribution. In moderately skewed or asymmetrical distribution a very important relationship
exists among these three measures of central tendency. In such distributions the distance between the mean and median is about one-third of the distance between the mean and mode, as will be clear from the diagrams 1 and 2. Karl Pearson expressed this relationship as:

Mode = mean - 3 [mean - median]

Mode = 3 median - 2 mean

Knowing any two values, the third can be computed.

This is about the special kind of distribution which you never see on GMAT.

Again if set is for example: {1,1,1,5,7}
Mean=5
Median=1
Mode=1

Put these values in the formula in red. You'll see the equation won't hold true.

I wouldn't advise to study this source in GMAT preparation.
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