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Bunuel
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Bunuel
Station Q is to the East of Station T. At 12 noon, a train starts from Station Q and travels at a constant speed of x mph towards Station T. At 12 noon of the same day, another train starts from Station T and travels at a constant speed of y mph towards Station Q. At what time will the trains meet?

(1) y = 4x/3
(2) x = 100 mph


­
Station Q is to the left of Station T. And two trains start exactly at 12 noon, from both stations Q and T.

The speeds of the train from stations Q and T are x mph and y mph respectively.

We need to find the time of meet = T = ?

Speed = Distance / Time

T = Distance / Relative speed

Statement 1:

(1) y = 4x/3

T = Distance / ( x + 4x/3)

Since, we don’t know the values of Distance, or the variable x. Hence, Insufficient.

Statement 2:

(2) x = 100 mph

we don’t know the values of y and distance. Hence, Insufficient.

Combining statements 1 and 2, we get

x = 100 mph.

y = 4x/3 = 400/3 mph.

Time = distance / (100 + 400/3)

Since distance is not given. Hence, Insufficient

Option E
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Let the distance between the two stations = D
They meet when time = distance/combined speed = D/(x + y)

(1) y=4x/3
Meeting time= D/(x+4x/3) = 3D/7x
D and x are unknown
Hence, insufficient

(2) x=100mph
Meeting time= D/(100+y)
D and y are unknown.
Hence, insufficient

Combining both
Meeting time= D/(100+400/3) =3D/700
We can’t find the meeting time of train without distance. Hence, insufficient.

Answer: E
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We need to find the meeting point but for that we need to know the distance between them.

Option 1:
Time to meet will be Distance /(sum of speed)
D/(x+4x/3)

Not sufficient
Option 2:
X=100 no info about y, nor we know distance hence not sufficient

Option 1+2:
from both the options also we don't know about the distance between T & Q hence option E should be the answer
Bunuel
Station Q is to the East of Station T. At 12 noon, a train starts from Station Q and travels at a constant speed of x mph towards Station T. At 12 noon of the same day, another train starts from Station T and travels at a constant speed of y mph towards Station Q. At what time will the trains meet?

(1) y = 4x/3
(2) x = 100 mph


­
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Station Q is to the East of Station T. At 12 noon, a train starts from Station Q and travels at a constant speed of x mph towards Station T. At 12 noon of the same day, another train starts from Station T and travels at a constant speed of y mph towards Station Q. At what time will the trains meet?

(1) y = 4x/3
(2) x = 100 mph

Here, the distance between the two station is unknown. So it is not possible to find the meeting time of two trains without knowing the distance.
Time of meet = Distance/Sum of Speeds of Train
In both (1)&(2) either speed is given or relation between them. But there is no info about distance. Hence, insufficient to find the meeting time of trains.

E
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