Bunuel
Taps A and C can fill a tank in 5 and 7 hrs respectively. Taps B and D can drain a full tank in 6 and 8 hrs. Respectively. Taps A and B are opened at 6 a.m. and6.30 a. m. respectively, till 65% of the tank is filled. Then, C and D are also opened. At what time will the tank get filled?
A. 1025/43 hrs
B. 1134/43 hrs
C. 1249/43 hrs
D. 1312/43 hrs
E. 1345/43 hrs
Solution:The rates of taps A, B, C, and D are 1/5, 1/6, 1/7, and 1/8, respectively.
We can let x be the number of hours tap A is open until 65% of the tank is filled. Thus, tap B is open for (x - 1/2) hours, and we can create the equation:
(1/5)(x) - (1/6)(x - 1/2) = 65/100
x/5 - x/6 + 1/12 = 13/20
Multiplying the equation by 60, we have:
12x - 10x + 5 = 39
2x = 34
x = 17
Since C and D are opened when the tank is 65% filled (after A has been operating for 17 hours, B has been operating for 16 1/2 hours, and both A and B will remain open until the tank is filled), we can create an equation where y is the number of hours needed to fill the remaining 35% of the tank:
y(1/5 - 1/6 + 1/7 - 1/8) = 35/100
y(1/30 + 1/56) = 7/20
86y/(30 * 56) = 7/20
y = (7 * 30 * 56)/(20 * 86)
y = (7 * 3 * 14)/43 = 294/43
Therefore, it takes 17 + 294/43 = (731 + 294)/43 = 1025/43 hours to fill the tank completely.
Answer: A