Bunuel
Ten years ago, Dorothy deposited a certain amount of money in Account A at a 3% simple annual interest rate. At the same time, Marla deposited another amount in Account B at a 4% simple annual interest rate. If there were no withdrawals or deposits during the 10 years since the deposits, is the current interest in A greater than that in B?
(1) The amount invested in Account A was $1,000 more than the amount invested in Account B.
(2) The investment in Account A obtained interest of $300 last year.
Solution
Step 1: Analyse Question Stem
• Based on the given information let’s make the following table:

• We need to find out if current interest in A is greater than that in B.
o Or, we need to find if \(\frac{3a}{10} > \frac{4b}{10} \)
Or, if \( 3a > 4b ⟹ \frac{a}{b} > \frac{4}{3}\)
Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE
Statement 1: The amount invested in Account A was $1,000 more than the amount invested in Account B.
• According to this statement: \(a = b + 1000 ⟹ \frac{a}{b} = 1 + \frac{1000}{b}\)
• However, we don’t know the value of b so we cannot find if \( \frac{a}{b} > \frac{4}{3}\) or not.
Hence, statement 1 is NOT sufficient and we can eliminate answer Options A and D.
Statement 2: The investment in Account A obtained interest of $300 last year.
• According to this statement: \(\frac{a*1*3}{100} = $300 ⟹ a = $10,000\)
• However, we don’t know the value of b so, we cannot find if \( \frac{a}{b} > \frac{4}{3}\) or not.
Hence, statement 2 is also NOT sufficient and we can eliminate answer Option B.
Step 3: Analyse Statements by combining.
• From statement 1: \( a = b + 1000………..Eq.(i)\)
• From statement 2: \( a = $10000…..Eq.(ii)\)
• On combining two statements,
o We know the value of a.
o With the eq.(i) and Eq.(ii), we can easily find out the value of b,
Then we can find out if 3a > 4b or not.
Thus, the correct answer is
Option C.