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Re: The 16 players in a chess tournament must each play every other player [#permalink]
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Kimberly77 wrote:

Hi BrentGMATPrepNow, I calculate it by listings as below and not sure why is not right?
Player 16 against Player 15 ... 1st game
Player 15 against Player 14 ... 2nd game
Player 14 against Player 13 ... 3rd game
....
Player 2 against Player 1 ... 15th game

So there are 15 chess games will be played in the tournament.


The question tells us that The 16 players in a chess tournament [i]must each play every other player in the first round of the tournament[/i]
And your solution, Player 16 plays only one game (against Player 15)
In actuality (to follow the conditions set out in the question), Player 16 must play Player 15, Player 14, Player 13, Player 12, . . . . Player 3, Player 2 and Player 1.
Similarly, Player 15 must play Player 16, Player 14, Player 13, Player 12, . . . . Player 3, Player 2 and Player 1.
Similarly, Player 14 must play Player 16, Player 15, Player 13, Player 12, . . . . Player 3, Player 2 and Player 1.
As you can see, I've already listed more than 15 games.
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Re: The 16 players in a chess tournament must each play every other player [#permalink]
BrentGMATPrepNow wrote:
Kimberly77 wrote:

Hi BrentGMATPrepNow, I calculate it by listings as below and not sure why is not right?
Player 16 against Player 15 ... 1st game
Player 15 against Player 14 ... 2nd game
Player 14 against Player 13 ... 3rd game
....
Player 2 against Player 1 ... 15th game

So there are 15 chess games will be played in the tournament.


The question tells us that The 16 players in a chess tournament [i]must each play every other player in the first round of the tournament[/i]
And your solution, Player 16 plays only one game (against Player 15)
In actuality (to follow the conditions set out in the question), Player 16 must play Player 15, Player 14, Player 13, Player 12, . . . . Player 3, Player 2 and Player 1.
Similarly, Player 15 must play Player 16, Player 14, Player 13, Player 12, . . . . Player 3, Player 2 and Player 1.
Similarly, Player 14 must play Player 16, Player 15, Player 13, Player 12, . . . . Player 3, Player 2 and Player 1.
As you can see, I've already listed more than 15 games.


Thanks BrentGMATPrepNow, Get it and see why now. :please:
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Re: The 16 players in a chess tournament must each play every other player [#permalink]
Hi All, kindly evaluate my approach: based on Brent concept, 4stages will be there as with each stage player is getting halved. So in stage 16player will play against 15others total no of games will be 16*15/2 (divided by 2 as duplicacy is there player 1 playing player 2 and player 2playing against player 1 counted twice). similarly, stage2: 8*7/2 stage 3: 4*3/2 and stage 4: 2*1/2 =155
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Re: The 16 players in a chess tournament must each play every other player [#permalink]
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