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Re: The 38 movies in the video store fall into the following three [#permalink]
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saintforlife
The 38 movies in the video store fall into the following three categories: 10 action, 20 drama, and 18 comedy. However, some movies are classified under more than one category: 5 are both action and drama, 3 are both action and comedy, and 4 are both drama and comedy. How many action-drama-comedies are there?

Hi Saint,

Check if this works for you, quite basic method though

Given........
Total = 38
A=10
D=20
C=18
AD=5
AC=3
DC=4
ALL=x (Assume action-drama-comedies be x)

At first we have to remove the movies that belong to all (i.e.action-drama-comedy) categories from every subset.

Total = 38
A=10 - x
D=20 - x
C=18 - x
AD only =5 - x
AC only =3 - x
DC only =4 - x
ALL=x

At second step we have to remove movies that belong to only two categories (AD only, AC only, DC only) from the main subsets (i.e A, D, C)

So we have that,

A only =(10 - x) - (5-x) - (3-x)
D only =(20 - x) - (5-x) - (4-x)
C only =(18 - x) - (3-x) - (4-x)
AD only =5 - x
AC only =3 - x
DC only =4 - x
ALL=x

So finally we have that,
Total = A only + D only + C only + AD only + AC only + DC only + ALL
38 = 2 + x + 11 + x + 11 + x + 5 - x + 3 - x + 4 - x + x
38 = 36 + x
x = 2

This method is just the algebraical version of venn diagram. IMO solving thru venn diagram would be much easier and faster though.

Hope that helps! :)
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Re: The 38 movies in the video store fall into the following three [#permalink]
Just curious to know, why we can't apply the formula below:

= action+drama+comedy-action&drama-action&comedy-drama&comedy-2*all
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Re: The 38 movies in the video store fall into the following three [#permalink]
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arorni
Just curious to know, why we can't apply the formula below:

= action+drama+comedy-action&drama-action&comedy-drama&comedy-2*all

I'm also wondering this.
Bunuel , can you explain why we don't multiply All by 2?
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Re: The 38 movies in the video store fall into the following three [#permalink]
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scubaVC
arorni
Just curious to know, why we can't apply the formula below:

= action+drama+comedy-action&drama-action&comedy-drama&comedy-2*all

I'm also wondering this.
Bunuel , can you explain why we don't multiply All by 2?

ADVANCED OVERLAPPING SETS PROBLEMS: https://gmatclub.com/forum/advanced-over ... 44260.html
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Re: The 38 movies in the video store fall into the following three [#permalink]
The 38 movies in the video store fall into the following three categories: 10 action; 20 drama; 18 comedy
5 are both action and drama; 3 are both action and comedy; 4 are both drama and comedy
How many action-drama-comedies are there?

38=10+20+18-5-3-4
38=36
38-36=ADC

Answer -> 2
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Re: The 38 movies in the video store fall into the following three [#permalink]
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Genoa2000
Bunuel

{Total} = {action} + {drama} + {comedy} - {action&drama+action&comedy+drama&comedy} + {action&drama&comedy}


Sorry to bother you Bunuel but I have a doubt about this.

I didn't really understand the concept of "(sum of 2 - group overlaps)" that you introduced in the thread you linked.

How did you consider "{action&drama+action&comedy+drama&comedy}" as a "sum of 2 - group overlaps"?

Thank you in advance!

This is explained in detail here: ADVANCED OVERLAPPING SETS PROBLEMS - https://gmatclub.com/forum/advanced-over ... 44260.html
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Re: The 38 movies in the video store fall into the following three [#permalink]
Bunuel
Genoa2000
Bunuel

{Total} = {action} + {drama} + {comedy} - {action&drama+action&comedy+drama&comedy} + {action&drama&comedy}


 
Sorry to bother you Bunuel but I have a doubt about this.

I didn't really understand the concept of "(sum of 2 - group overlaps)" that you introduced in the thread you linked.

How did you consider "{action&drama+action&comedy+drama&comedy}" as a "sum of 2 - group overlaps"?

Thank you in advance!
This is explained in detail here: ADVANCED OVERLAPPING SETS PROBLEMS - https://gmatclub.com/forum/advanced-ove ... 44260.html
­Are you unable to explain it? I have read it multiple times and still am not sure why you use that formula and not the other one
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Re: The 38 movies in the video store fall into the following three [#permalink]
arorni
Just curious to know, why we can't apply the formula below:

= action+drama+comedy-action&drama-action&comedy-drama&comedy-2*all

i don't really know where your formula comes from, but the point here is that if we want to calculate the UNION of 3 overlapping sets A B C
we have to add the 3 sets all together: A+B+C
the problem now is that the section that overlap A&B, A&C, B&C have been counted twice (think about adding 2 sets only) and the section that is in the intersection of all 3 A&B&C has been counted 3 times. for this reason we remove A&B, A&C, B&C ONE time each:

A+B+C - ( A&B + A&C + B&C)

at this point the issue is that we have removed the duplicates for the 2-intersections, but we also removed the intersection among A&B, A&C, B&C, that is A&B&C . how many times have we removed it? 3 times! look at the formula, we removed ( A&B + A&C + B&C) from A+B+C.

BUT we know that A&B&C was triple counted initially (see the highlight). So A+B+C - ( A&B + A&C + B&C) does not contain the area of the triple intersection, and thus, we have to add it to obtain the formula used in this kind of problems:

A+B+C - ( A&B + A&C + B&C) + A&B&C = AUB
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Re: The 38 movies in the video store fall into the following three [#permalink]
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