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The age of the Earth is approximately 1.3*10^17 seconds, and one year

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angelfire213
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The age of the Earth is approximately 1.3*10^17 seconds, and one year [#permalink] New post  Updated on: 30 Oct 2017, 04:43
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The age of the Earth is approximately \(1.3*10^{17}\) seconds, and one year is approximately \(3.2 * 10^7\) seconds. Which of the following is closest to the age of the Earth in years?

A. \(2.5 *10^9\)

B. \(4.1 * 10^9\)

C. \(1.9* 10^{10}\)

D. \(2.5* 10^{11}\)

E. \(4.1 * 10^{11}\)
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Originally posted by angelfire213 on 28 Oct 2014, 17:37.
Last edited by Bunuel on 30 Oct 2017, 04:43, edited 2 times in total.
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PareshGmat
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Re: The age of the Earth is approximately 1.3*10^17 seconds, and one year [#permalink] New post  28 Oct 2014, 21:09
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1 Year \(= 3.2 * 10^7\) seconds, so \(1.3*10^{17}\) seconds would be =

\(\frac{1.3 * 10^{17}}{3.2 * 10^7} = \frac{130*10^{15}}{32*10^6} = 4.1*10^9\) Years

Answer = B
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Re: The age of the Earth is approximately 1.3*10^17 seconds, and one year [#permalink] New post  29 Oct 2014, 04:04
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angelfire213 wrote:
The age of the Earth is approximately 1.3*10^17 seconds, and one year is approximately 3.2 * 10^7 seconds. Which of the following is closest to the age of the Earth in years?

A. 2.5 *10^9
B. 4.1 * 10^9
C. 1.9* 10^10
D. 2.5* 10^11
E. 4.1 * 10^11


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Re: The age of the Earth is approximately 1.3*10^17 seconds, and one year [#permalink] New post  24 Oct 2015, 13:07
I wanted to ask for some help, since I cannot find my mistake.
What I tried to do was:

\(\frac{1.3*10^{17}}{3.2*10^7} = 1.3*3.2*10^7 = 4.16*10^7\)

What am I doing wrong?

Thanks in advance!
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Re: The age of the Earth is approximately 1.3*10^17 seconds, and one year [#permalink] New post  25 Oct 2015, 05:53
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petocities wrote:
I wanted to ask for some help, since I cannot find my mistake.
What I tried to do was:

1.3*10^17/3.2*10^7 = 1.3*3.2*10^7 = 4.16*10^7

What am I doing wrong?

Thanks in advance!


1.3*10^17/3.2*10^7 = 1.3/3.2*10^10 = ~0.4*10^10 = 4*10*9.
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Re: The age of the Earth is approximately 1.3*10^17 seconds, and one year [#permalink] New post  25 Oct 2015, 10:40
Bunuel wrote:
petocities wrote:
I wanted to ask for some help, since I cannot find my mistake.
What I tried to do was:

1.3*10^17/3.2*10^7 = 1.3*3.2*10^7 = 4.16*10^7

What am I doing wrong?

Thanks in advance!


1.3*10^17/3.2*10^7 = 1.3/3.2*10^10 = ~0.4*10^10 = 4*10*9.


Ah of course, silly mistake. Thanks a lot Bunuel
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Re: The age of the Earth is approximately 1.3*10^17 seconds, and one year [#permalink] New post  20 Dec 2017, 04:12
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angelfire213 wrote:
The age of the Earth is approximately \(1.3*10^{17}\) seconds, and one year is approximately \(3.2 * 10^7\) seconds. Which of the following is closest to the age of the Earth in years?

A. \(2.5 *10^9\)

B. \(4.1 * 10^9\)

C. \(1.9* 10^{10}\)

D. \(2.5* 10^{11}\)

E. \(4.1 * 10^{11}\)


Or simply approximate:

1.3/3.2 is a bit less than 1/2 (i.e. less than 0.5).
\(10^{17}/10^7\) will give \(10^{10}\).

Of the given options, \(4.1 * 10^9\) works.
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Re: The age of the Earth is approximately 1.3*10^17 seconds, and one year [#permalink] New post  20 Feb 2018, 20:40
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I'm confused. How come we didn't convert from secs to years? We just straight up divide the two (in secs) and that gets us an answer in "years"?
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Re: The age of the Earth is approximately 1.3*10^17 seconds, and one year [#permalink] New post  10 Aug 2020, 10:46
angelfire213 wrote:
The age of the Earth is approximately \(1.3*10^{17}\) seconds, and one year is approximately \(3.2 * 10^7\) seconds. Which of the following is closest to the age of the Earth in years?

A. \(2.5 *10^9\)

B. \(4.1 * 10^9\)

C. \(1.9* 10^{10}\)

D. \(2.5* 10^{11}\)

E. \(4.1 * 10^{11}\)



To find the age = Age in sec/Year in sec

=1.3*10^{17}/3.2 * 10^7=130*10^9/32=4.1*10^9
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Re: The age of the Earth is approximately 1.3*10^17 seconds, and one year [#permalink] New post  23 Feb 2023, 13:27
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