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18 Aug 2017, 03:03
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D
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Difficulty:
45%
(medium)
Question Stats:
73% (02:05) correct
27%
(02:30)
wrong
based on 340
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The ‘Amazing Soft Drink’ company interviewed 'k' consumers for market research study. The study found that \(\frac{2}{5}\) of consumers preferred Zing cola to Diet Zing Cola. Of those who preferred Diet Zing, \(\frac{1}{6}\) preferred Caffeine free Diet Zing. How many consumers, in terms of 'k' , did not prefer Caffeine free Diet Zing?
A. \(\frac{k}{11}\)
B. \(\frac{k}{10}\)
C. \(\frac{7k}{15}\)
D. \(\frac{9k}{10}\)
E. \(\frac{10k}{11}\)
A. \(\frac{k}{11}\)
B. \(\frac{k}{10}\)
C. \(\frac{7k}{15}\)
D. \(\frac{9k}{10}\)
E. \(\frac{10k}{11}\)
18 Aug 2017, 03:18
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HolaMaven
Hi...
Two ways..
1) proper method..
Let's find how many prefer..
1/6 of free diet... Free diet- how many?? 1-2/5 = 3/5 of 'k'..
So 1/6 of 3/5 of k= \(\frac{1}{6}*\frac{3}{5}*k=\frac{k}{10}\)
Total who do not prefer =k- k/10=9k/10
D
2) give a value to K..
Let k =10..
3/5 of 10 or 6 prefer diet..
1/6 of these prefer free diet =6*1/6=1..
So who do not prefer=10-1=9..
Substitute k as 10 and find which matches.
D =9k/10=9*10/10=9
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18 Aug 2017, 04:32
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1. \(\frac{2}{5}\) preferred Zing Cola to Diet Zing Cola, thus those who prefer Diet Zing is \(\frac{3}{5}\).
2. From this \(\frac{3}{5}\), \(\frac{1}{6}\) prefer caffeine free. Thus, compared with K, this would be \(\frac{3}{5}\) * \(\frac{1}{6}\), which is \(\frac{1}{10}\)
3. Asked : what ratio of people who don't like the caffeine? 1 - \(\frac{1}{10}\) : \(\frac{9}{10}\)
Is it true 600-700 question? Or do I miss something?
2. From this \(\frac{3}{5}\), \(\frac{1}{6}\) prefer caffeine free. Thus, compared with K, this would be \(\frac{3}{5}\) * \(\frac{1}{6}\), which is \(\frac{1}{10}\)
3. Asked : what ratio of people who don't like the caffeine? 1 - \(\frac{1}{10}\) : \(\frac{9}{10}\)
Is it true 600-700 question? Or do I miss something?
