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# The ‘Amazing Soft Drink’ company interviewed 'k' consumers for market

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Manager
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Joined: 12 Aug 2017
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The ‘Amazing Soft Drink’ company interviewed 'k' consumers for market  [#permalink]

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18 Aug 2017, 03:03
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45% (medium)

Question Stats:

63% (02:03) correct 37% (02:02) wrong based on 100 sessions

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The ‘Amazing Soft Drink’ company interviewed 'k' consumers for market research study. The study found that $$\frac{2}{5}$$ of consumers preferred Zing cola to Diet Zing Cola. Of those who preferred Diet Zing, $$\frac{1}{6}$$ preferred Caffeine free Diet Zing. How many consumers, in terms of 'k' , did not prefer Caffeine free Diet Zing?

A. $$\frac{k}{11}$$
B. $$\frac{k}{10}$$
C. $$\frac{7k}{15}$$
D. $$\frac{9k}{10}$$
E. $$\frac{10k}{11}$$

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The ‘Amazing Soft Drink’ company interviewed 'k' consumers for market  [#permalink]

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18 Aug 2017, 03:18
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HolaMaven wrote:
The ‘Amazing Soft Drink’ company interviewed 'k' consumers for market research study. The study found that $$\frac{2}{5}$$ of consumers preferred Zing cola to Diet Zing Cola. Of those who preferred Diet Zing, $$\frac{1}{6}$$ preferred Caffeine free Diet Zing. How many consumers, in terms of 'k' , did not prefer Caffeine free Diet Zing?

A. $$\frac{k}{11}$$
B. $$\frac{k}{10}$$
C. $$\frac{7k}{15}$$
D. $$\frac{9k}{10}$$
E. $$\frac{10k}{11}$$

Hi...

Two ways..

1) proper method..
Let's find how many prefer..
1/6 of free diet... Free diet- how many?? 1-2/5 = 3/5 of 'k'..
So 1/6 of 3/5 of k= $$\frac{1}{6}*\frac{3}{5}*k=\frac{k}{10}$$
Total who do not prefer =k- k/10=9k/10
D

2) give a value to K..
Let k =10..
3/5 of 10 or 6 prefer diet..
1/6 of these prefer free diet =6*1/6=1..
So who do not prefer=10-1=9..

Substitute k as 10 and find which matches.
D =9k/10=9*10/10=9
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The ‘Amazing Soft Drink’ company interviewed 'k' consumers for market  [#permalink]

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18 Aug 2017, 04:32
1. $$\frac{2}{5}$$ preferred Zing Cola to Diet Zing Cola, thus those who prefer Diet Zing is $$\frac{3}{5}$$.
2. From this $$\frac{3}{5}$$, $$\frac{1}{6}$$ prefer caffeine free. Thus, compared with K, this would be $$\frac{3}{5}$$ * $$\frac{1}{6}$$, which is $$\frac{1}{10}$$
3. Asked : what ratio of people who don't like the caffeine? 1 - $$\frac{1}{10}$$ : $$\frac{9}{10}$$
Is it true 600-700 question? Or do I miss something?
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Re: The ‘Amazing Soft Drink’ company interviewed 'k' consumers for market  [#permalink]

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18 Aug 2017, 04:45
septwibowo wrote:
1. $$\frac{2}{5}$$ preferred Zing Cola to Diet Zing Cola, thus those who prefer Diet Zing is $$\frac{3}{5}$$.
2. From this $$\frac{3}{5}$$, $$\frac{1}{6}$$ prefer caffeine free. Thus, compared with K, this would be $$\frac{3}{5}$$ * $$\frac{1}{6}$$, which is $$\frac{1}{10}$$
3. Asked : what ratio of people who don't like the caffeine? 1 - $$\frac{1}{10}$$ : $$\frac{9}{10}$$
Is it true 600-700 question? Or do I miss something?

It is not asking to find the ratio. It is asking to find the fraction of people who dont like caffeine so answer is only $$\frac{9k}{10}$$
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Re: The ‘Amazing Soft Drink’ company interviewed 'k' consumers for market  [#permalink]

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18 Aug 2017, 04:48
1
HolaMaven wrote:
septwibowo wrote:
1. $$\frac{2}{5}$$ preferred Zing Cola to Diet Zing Cola, thus those who prefer Diet Zing is $$\frac{3}{5}$$.
2. From this $$\frac{3}{5}$$, $$\frac{1}{6}$$ prefer caffeine free. Thus, compared with K, this would be $$\frac{3}{5}$$ * $$\frac{1}{6}$$, which is $$\frac{1}{10}$$
3. Asked : what ratio of people who don't like the caffeine? 1 - $$\frac{1}{10}$$ : $$\frac{9}{10}$$
Is it true 600-700 question? Or do I miss something?

It is not asking to find the ratio. It is asking to find the fraction of people who dont like caffeine so answer is only $$\frac{9k}{10}$$

Ah sure! thanks!
So, all we have to do is to add this ration with the number of respondents : $$\frac{9}{10}$$ * k, which is $$\frac{9k}{10}$$.
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Re: The ‘Amazing Soft Drink’ company interviewed 'k' consumers for market  [#permalink]

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18 Aug 2017, 05:08
1
HolaMaven wrote:
The ‘Amazing Soft Drink’ company interviewed 'k' consumers for market research study. The study found that $$\frac{2}{5}$$ of consumers preferred Zing cola to Diet Zing Cola. Of those who preferred Diet Zing, $$\frac{1}{6}$$ preferred Caffeine free Diet Zing. How many consumers, in terms of 'k' , did not prefer Caffeine free Diet Zing?

A. $$\frac{k}{11}$$
B. $$\frac{k}{10}$$
C. $$\frac{7k}{15}$$
D. $$\frac{9k}{10}$$
E. $$\frac{10k}{11}$$

One can also assume a value for k and then do it. Say k = 30

Since 2/5th preferred Zing, 3/5th preferred Diet Zing. So 18 preferred it.
Of these 18, 1/6th preferred Caffeine Diet Zing so 3 preferred it. This means 27 did not.

Put k = 30. Whichever option gives 27, is the answer.

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Re: The ‘Amazing Soft Drink’ company interviewed 'k' consumers for market  [#permalink]

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03 Nov 2017, 21:15
VeritasPrepKarishma wrote:
HolaMaven wrote:
The ‘Amazing Soft Drink’ company interviewed 'k' consumers for market research study. The study found that $$\frac{2}{5}$$ of consumers preferred Zing cola to Diet Zing Cola. Of those who preferred Diet Zing, $$\frac{1}{6}$$ preferred Caffeine free Diet Zing. How many consumers, in terms of 'k' , did not prefer Caffeine free Diet Zing?

A. $$\frac{k}{11}$$
B. $$\frac{k}{10}$$
C. $$\frac{7k}{15}$$
D. $$\frac{9k}{10}$$
E. $$\frac{10k}{11}$$

One can also assume a value for k and then do it. Say k = 30

Since 2/5th preferred Zing, 3/5th preferred Diet Zing. So 18 preferred it.
Of these 18, 1/6th preferred Caffeine Diet Zing so 3 preferred it. This means 27 did not.

Put k = 30. Whichever option gives 27, is the answer.

Hi Karishma,

1/6 of 3/5 preferred Caffeine diet zing hence I thought 5/6 of 3/5 did not prefer caffeine diet
But 5/6 of 3/5 (K) = K/2

why am I not getting 9K/10
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Re: The ‘Amazing Soft Drink’ company interviewed 'k' consumers for market &nbs [#permalink] 03 Nov 2017, 21:15
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