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Math Expert V
Joined: 02 Sep 2009
Posts: 55231
The area of the circle in the figure above is 25π . What is the perime  [#permalink]

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Difficulty:   35% (medium)

Question Stats: 72% (02:00) correct 28% (02:02) wrong based on 20 sessions

### HideShow timer Statistics The area of the circle in the figure above is 25π . What is the perimeter of the inscribed equilateral triangle?

A. $$15\sqrt{3}$$

B. 15

C. $$7.5\sqrt{3}$$

D. 7.5

E. $$2.5\sqrt{3}$$

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The area of the circle in the figure above is 25π . What is the perime  [#permalink]

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Bunuel wrote: The area of the circle in the figure above is 25π . What is the perimeter of the inscribed equilateral triangle?

A. $$15\sqrt{3}$$

B. 15

C. $$7.5\sqrt{3}$$

D. 7.5

E. $$2.5\sqrt{3}$$

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The attachment image008 (1).jpg is no longer available

Area pf the circle$$= πr^2 = 25π$$

i.e. $$r = 5$$

Join the vertices of triangle with centre of the circle so that equilateral triangle gets divided in three 120º-30º-30º triangles where 120º is teh angle drawn at the centre of the circle

Divide the 120º-30º-30º triangle into two 90º-30º-60º triangles which hahaev hypotenuse = 5
i.e. Side opposite to 30º = 5/2
and side opposite to 60º = 5√3/2 which is half of the length of the side of equilateral

i.e. side of equilateral triangle $$= 2*5√3/2 = 5√3$$
hence, Perimeter of the equilateral $$= 3*5√3 = 15√3$$

Answer: option A
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GMAT 1: 620 Q45 V31 Re: The area of the circle in the figure above is 25π . What is the perime  [#permalink]

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height of equi triangle is root3/2 side and median divides height in ratio 2:1 so 2/3*root3/2 side = 5( pi r^2 = pi*5^2)
so side = 5*3/root3
perimeter = 3 * side
5*3*root3*root3/root3 = 15*root3 Re: The area of the circle in the figure above is 25π . What is the perime   [#permalink] 11 Sep 2018, 18:49
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# The area of the circle in the figure above is 25π . What is the perime

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