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23 May 2020, 08:38
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The average (arithmetic mean) of 3 positive integers, x, y, and z, is 20. If the average (arithmetic mean) of x and y is 9, what is the average (arithmetic mean) of y and z ?
(1) The average (arithmetic mean) of x and z is 22.5
(2) y = 5x
DS20412
(1) The average (arithmetic mean) of x and z is 22.5
(2) y = 5x
DS20412
23 May 2020, 09:21
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Bunuel
The average (arithmetic mean) of 3 positive integers, x, y, and z, is 20. If the average (arithmetic mean) of x and y is 9, what is the average (arithmetic mean) of y and z ?
(1) The average (arithmetic mean) of x and z is 22.5
(2) y = 5x
DS20412
(1) The average (arithmetic mean) of x and z is 22.5
(2) y = 5x
DS20412
Question: \(\frac{y+z}{2} =\) ?
Given: x+y+z = 20*3 = 60 and x+y = 18 i.e. z = 42
So we need either x or y to answer the question
Statement 1: x+z = 45
i.e. x = 3
i.e. y = 15
SUFFICIENT
Statement 2: y = 5x
x+y = 18
i.e. 6x = 18 and x = 3
i.e. y = 15
SUFFICIENT
Answer: Option D
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24 May 2020, 05:51
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Bunuel
The average (arithmetic mean) of 3 positive integers, x, y, and z, is 20. If the average (arithmetic mean) of x and y is 9, what is the average (arithmetic mean) of y and z ?
(1) The average (arithmetic mean) of x and z is 22.5
(2) y = 5x
DS20412
(1) The average (arithmetic mean) of x and z is 22.5
(2) y = 5x
DS20412
Given x + y + z = 60.
x + y = 18
y + z = ?
Statement 1: The average (arithmetic mean) of x and z is 22.5
=> x + z = 45
=> y = 15.
=> x = 3
=> z = 42.
Since we have all the values, we can easily calculate the value of y+ z, thus, the average of the same.
So Sufficient.
Statement 2: y = 5x.
x + y = 18
=> 6x = 18.
=> x = 3.
=> y = 15.
=> z = 42.
Since we have all the values, we can easily calculate the value of y+ z, thus, the average of the same.
So Sufficient.
Answer D.
