Bunuel
The average (arithmetic mean) of 4 different integers is 75. If the largest integer is 90, what is the least possible value of the smallest integer?
A. 1
B. 19
C. 29
D. 30
E. 33
Kudos for a correct solution. MAGOOSH OFFICIAL SOLUTION:Attachment:
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FAQ: Why can't the values be 90, 90, 90, and 30?The question states that we have four different integers, so we can only have one 90. The other numbers can't also be 90.
FAQ: After a little calculation, we get a sum for 3 other integers equal to 210. Why can't the smallest integer be 1 for those 3 integers?The trick here is in noting that the largest integer is 90. So not only do the other three numbers have to total 210, but none of them can be larger than 90. If the smallest were 1, then the last two would have to add up to 209. This is impossible.
FAQ: Why are the numbers in consecutive order: 88, 89, and 90?We are not choosing them because they are consecutive. This is the result of following the parameter set by the problem. No number is larger than 90. So, to find the least value of a number, we stack as much "weight" on the other numbers, and choose the next largest number possible after 90 (89). And since the numbers are all different, we have to again choose the next largest number (88). Thus 88 + 89 + 90.