NEW HERE? LEARN MORE
closeclose
Last visit was: 24 Apr 2024, 03:19 It is currently 24 Apr 2024, 03:19
Decision Tracker
My Rewards
New posts
New comers' posts

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel

The average (arithmetic mean) of four packages is 15 pounds. If the we

SORT BY:
Date
Kudos
Tags:
Find Similar Topics 
Show Tags
Hide Tags
User avatar
L
Bunuel
Math Expert
Joined: 02 Sep 2009
Posts: 92901
Own Kudos [?]: 618694 [0]
Given Kudos: 81586
Send PM
CAT Tests Forum Quiz Mode
The average (arithmetic mean) of four packages is 15 pounds. If the we [#permalink] New post   12 Jun 2019, 02:00
Expert Reply
00:00
A
B
C
D
E

Difficulty:

25% (medium)

Question Stats:

75% (01:57) correct 25% (02:11) wrong based on 64 sessions
Hide Show timer Statistics
The average (arithmetic mean) of four packages is 15 pounds. If the weight of the first package is x, and each package weighs twice as much as the previous package, which of the following CANNOT be the total weight, in pounds, of any combination of the packages?

A. 12
B. 24
C. 44
D. 46
E. 52
ShowHide Answer
Official Answer
D
User avatar
L
nick1816
Retired Moderator
Joined: 19 Oct 2018
Posts: 1878
Own Kudos [?]: 6295 [1]
Given Kudos: 704
Location: India
Send PM
The average (arithmetic mean) of four packages is 15 pounds. If the we [#permalink] New post   Updated on: 12 Jun 2019, 14:38
1
Kudos
Weight of the boxes are k, 2k, 4k and 8k

k+2k+4k+8k/4 = 15
15k =60
k=4

Weight of the boxes are 4,8,16 and 32
Weight of each box is a multiple of 4, hence the weight of any combination of these boxes will also be a multiple of 4.

Option D is not a multiple of 4.

Bunuel wrote:
The average (arithmetic mean) of four packages is 15 pounds. If the weight of the first package is x, and each package weighs twice as much as the previous package, which of the following CANNOT be the total weight, in pounds, of any combination of the packages?

A. 12
B. 24
C. 44
D. 46
E. 52

Originally posted by nick1816 on 12 Jun 2019, 02:19.
Last edited by nick1816 on 12 Jun 2019, 14:38, edited 1 time in total.
User avatar
P
Lampard42
Senior Manager
Senior Manager
Joined: 22 Nov 2018
Posts: 446
Own Kudos [?]: 491 [0]
Given Kudos: 292
Location: India
GMAT 1: 640 Q45 V35
GMAT 2: 740 Q49 V41
Send PM
GMAT ToolKit User
Re: The average (arithmetic mean) of four packages is 15 pounds. If the we [#permalink] New post   12 Jun 2019, 02:24
Bunuel wrote:
The average (arithmetic mean) of four packages is 15 pounds. If the weight of the first package is x, and each package weighs twice as much as the previous package, which of the following CANNOT be the total weight, in pounds, of any combination of the packages?

A. 12
B. 24
C. 44
D. 46
E. 52


Sum of all packages=4*15; X+2X+4X+8X=60; 15X=60; X=4. So all combinations must be multiples of 4; 46 is not a multiple of 4 IMO D
User avatar
L
Archit3110
GMAT Club Legend
GMAT Club Legend
Joined: 18 Aug 2017
Status:You learn more from failure than from success.
Posts: 8019
Own Kudos [?]: 4095 [0]
Given Kudos: 242
Location: India
Concentration: Sustainability, Marketing
GMAT Focus 1:
545 Q79 V79 DI73
GPA: 4
WE:Marketing (Energy and Utilities)
Send PM
GMAT ToolKit User CAT Tests
Re: The average (arithmetic mean) of four packages is 15 pounds. If the we [#permalink] New post   12 Jun 2019, 03:18
Bunuel wrote:
The average (arithmetic mean) of four packages is 15 pounds. If the weight of the first package is x, and each package weighs twice as much as the previous package, which of the following CANNOT be the total weight, in pounds, of any combination of the packages?

A. 12
B. 24
C. 44
D. 46
E. 52


total weight = 60
and each package ; 4,8,16,32
so 46 sum is not possible
IMO D
User avatar
L
Arro44
Director
Director
Joined: 04 Jun 2018
Posts: 668
Own Kudos [?]: 733 [0]
Given Kudos: 362
Location: United States
Concentration: General Management, Finance
Schools: Sloan '22 (M) Cambridge "21 (A$)
GMAT 1: 730 Q47 V44
GPA: 3.4
Send PM
Reviews Badge
Re: The average (arithmetic mean) of four packages is 15 pounds. If the we [#permalink] New post   12 Jun 2019, 03:55
nick1816 wrote:
Weight of the boxes are k, 2k, 4k and 8k

k+2k+4k+8k/4 = 15
15k =60
k=4

Weight of the boxes are 4,8,16 and 32
Weight of each box is a multiple of 4, hence the weight of any combination of these boxes will also be a multiple of 4.

Option C is not a multiple of 4.

Bunuel wrote:
The average (arithmetic mean) of four packages is 15 pounds. If the weight of the first package is x, and each package weighs twice as much as the previous package, which of the following CANNOT be the total weight, in pounds, of any combination of the packages?

A. 12
B. 24
C. 44
D. 46
E. 52


Option C can be created by combining x + 2x + 8x (e.g. 4 + 8 + 32 = 40)

The right answer choice is D as we cannot create 46 from any possible combination of our four given numbers.
User avatar
L
ScottTargetTestPrep
Target Test Prep Representative
Joined: 14 Oct 2015
Status:Founder & CEO
Affiliations: Target Test Prep
Posts: 18753
Own Kudos [?]: 22043 [0]
Given Kudos: 283
Location: United States (CA)
Send PM
Re: The average (arithmetic mean) of four packages is 15 pounds. If the we [#permalink] New post   17 Jun 2019, 17:40
Expert Reply
Bunuel wrote:
The average (arithmetic mean) of four packages is 15 pounds. If the weight of the first package is x, and each package weighs twice as much as the previous package, which of the following CANNOT be the total weight, in pounds, of any combination of the packages?

A. 12
B. 24
C. 44
D. 46
E. 52


We can create the equation:

(x + 2x + 4x + 8x)/4 = 15

x + 2x + 4x + 8x = 60

15x = 60

x = 4

So the weights of the boxes are 4, 8, 16, and 32. We see that a combination of the packages could weigh 4 + 8 = 12, 8 + 16 = 24, 4 + 8 + 32 = 44 or 4 + 16 + 32 = 52.

Thus, we see that 46 cannot be the weight of a combination of any of the packages.

Answer: D
User avatar
P
LeoN88
BSchool Moderator
Joined: 08 Dec 2013
Posts: 686
Own Kudos [?]: 515 [0]
Given Kudos: 227
Location: India
Concentration: Nonprofit, Sustainability
Schools: ISB '23
GMAT 1: 630 Q47 V30
WE:Operations (Non-Profit and Government)
Send PM
Reviews Badge
Re: The average (arithmetic mean) of four packages is 15 pounds. If the we [#permalink] New post   17 Jun 2019, 17:49
Bunuel wrote:
The average (arithmetic mean) of four packages is 15 pounds. If the weight of the first package is x, and each package weighs twice as much as the previous package, which of the following CANNOT be the total weight, in pounds, of any combination of the packages?

A. 12
B. 24
C. 44
D. 46
E. 52


Weights: x, 2x, 4x and 8x
From average equation: 15x/4 = 15 so x=4
Weights: 4, 8, 16 and 32.

Now, the combination of weights must be a multiple of 4. D. 46 is not.
GMAT Club Bot
gmatclubot
Re: The average (arithmetic mean) of four packages is 15 pounds. If the we [#permalink]
17 Jun 2019, 17:49
Moderators:
Bunuel
Math Expert
92901 posts
yashikaaggarwal
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne
Main navigation
GMAT Resources
Partners
MBA Resources
www.gmac.com|www.mba.com | | GMAT Club Rules | Terms and Conditions