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The average weight of 10 men is increased by 1 ½ kg when one of the me

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The average weight of 10 men is increased by 1 ½ kg when one of the me  [#permalink]

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New post 08 Feb 2011, 11:30
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The average weight of 10 men is increased by 1 ½ kg when one of the men who weighs 68 kg is replaced by a new man. What is the weight of the new man?

(A) 80 kg

(B) 83 kg

(C) 70 kg

(D) 75 kg

(E) 85 kg
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Re: The average weight of 10 men is increased by 1 ½ kg when one of the me  [#permalink]

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New post 08 Feb 2011, 11:45
Since the average has increased by 1.5 kg, the weight of the man who stepped in must be equal to 68+10x1.5

68+15=83 Kg

Ans: 'B'
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Re: The average weight of 10 men is increased by 1 ½ kg when one of the me  [#permalink]

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New post 08 Feb 2011, 11:46
Lolaergasheva wrote:
The average weight of 10 men is increased by 1 ½ kg when one of the men who weighs 68 kg is replaced by a new man. What is the weight of the new man?

(A) 80 kg

(B) 83 kg

(C) 70 kg

(D) 75 kg

(E) 85 kg


The average weight of 10 men is increased by 1.5 kg means that total weight of 10 men increased by 1.5*10=15 kg. So the weight of the new man equals to the weight of the man who was replaced plus 15 kg = 68 + 15 = 83 kg.

Answer: B.
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Re: The average weight of 10 men is increased by 1 ½ kg when one of the me  [#permalink]

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New post 08 Feb 2011, 11:59
Total weight increase for the 10 men is 1.5*10=15. So the new man brings 68+15=83kg
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Re: The average weight of 10 men is increased by 1 ½ kg when one of the me  [#permalink]

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New post 09 Feb 2011, 07:31
10*x - Initial Total (and x is initial average)

=> (10x - 68 + y)/10 = x + 3/2

=> 10x - 68 + y = 10x + 15

=> y = 83
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Re: The average weight of 10 men is increased by 1 ½ kg when one of the me  [#permalink]

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New post 07 Sep 2017, 16:40
Lolaergasheva wrote:
The average weight of 10 men is increased by 1 ½ kg when one of the men who weighs 68 kg is replaced by a new man. What is the weight of the new man?

(A) 80 kg

(B) 83 kg

(C) 70 kg

(D) 75 kg

(E) 85 kg


We can let the initial average = x/10 in which x = the sum of the 10 men. Thus, the new average is:

(x/10) + 3/2 = (x/10) + 15/10 = (x + 15)/10

We can let n = the weight of the new man:

(x + 15)/10 = (x - 68 + n)/10

x + 15 = x - 68 + n

83 = n

Answer: B
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Re: The average weight of 10 men is increased by 1 ½ kg when one of the me  [#permalink]

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New post 08 Oct 2018, 03:21
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Re: The average weight of 10 men is increased by 1 ½ kg when one of the me   [#permalink] 08 Oct 2018, 03:21
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