NEW HERE? LEARN MORE
closeclose
Last visit was: 05 May 2024, 12:57 It is currently 05 May 2024, 12:57
Decision Tracker
My Rewards
New posts
New comers' posts

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel

The base of a vertical pillar with uniform cross section is a trapeziu

SORT BY:
Date
Kudos
Tags:
Find Similar Topics 
Show Tags
Hide Tags
User avatar
L
Bunuel
Math Expert
Joined: 02 Sep 2009
Posts: 93032
Own Kudos [?]: 621447 [7]
Given Kudos: 81751
Send PM
CAT Tests Forum Quiz Mode
The base of a vertical pillar with uniform cross section is a trapeziu [#permalink] New post   03 Apr 2020, 04:23
7
Bookmarks
Expert Reply
00:00
A
B
C
D
E

Difficulty:

65% (hard)

Question Stats:

67% (02:54) correct 33% (02:58) wrong based on 48 sessions
Hide Show timer Statistics
The base of a vertical pillar with uniform cross section is a trapezium whose parallel sides are of lengths 10 cm and 20 cm while the other two sides are of equal length. The perpendicular distance between the parallel sides of the trapezium is 12 cm. If the height of the pillar is 20 cm, then the total area, in sq cm, of all six surfaces of the pillar is

A. 1300
B. 1340
C. 1480
D. 1520
E. 1580


Are You Up For the Challenge: 700 Level Questions
ShowHide Answer
Official Answer
C
User avatar
L
CareerGeek
VP
VP
Joined: 20 Jul 2017
Posts: 1300
Own Kudos [?]: 3467 [1]
Given Kudos: 162
Location: India
Concentration: Entrepreneurship, Marketing
GMAT 1: 690 Q51 V30
WE:Education (Education)
Send PM
Re: The base of a vertical pillar with uniform cross section is a trapeziu [#permalink] New post   03 Apr 2020, 09:58
Bunuel wrote:
The base of a vertical pillar with uniform cross section is a trapezium whose parallel sides are of lengths 10 cm and 20 cm while the other two sides are of equal length. The perpendicular distance between the parallel sides of the trapezium is 12 cm. If the height of the pillar is 20 cm, then the total area, in sq cm, of all six surfaces of the pillar is

A. 1300
B. 1340
C. 1480
D. 1520
E. 1580


In the isosceles trapezium ABCD, ADE is a right angled triangle.
--> \(AD^2 = AE^2 + ED^2 = 12^2 + 5^2 = 169\)
--> \(AD = EC = 13\)

Note that all the sides of the trapezium forms 4 vertical walls of the pillar with height 20 cm and 2 horizontal surfaces with area as the area of trapezium

Area of vertical surfaces = \(10*20 + 13*20 + 13*20 + 20*20 = 56*20 = 1120\) sq.cm
Area of horizontal surfaces = \(2[\frac{1}{2}*(10 + 20)*12] = 30*12 = 360\) sq.cm

--> Total area = \(1120 + 360 = 1480\) sq. cm

Option C
Attachments

6.JPG
6.JPG [ 17.59 KiB | Viewed 3320 times ]

User avatar
G
preetamsaha
Senior Manager
Senior Manager
Joined: 14 Oct 2019
Status:Today a Reader; Tomorrow a Leader.
Posts: 346
Own Kudos [?]: 345 [0]
Given Kudos: 127
Location: India
GPA: 4
WE:Engineering (Energy and Utilities)
Send PM
Re: The base of a vertical pillar with uniform cross section is a trapeziu [#permalink] New post   04 Apr 2020, 09:26
Given, the non-parallel sides are equal. Let the non-parallel sides be x cm each
x= √(12^2 + 5^2) = 13
So, we have 6 faces, out of which 2 are trapezoid faces and 4 are rectangular faces.
Area of trapezium = 1/2(sum of two parallel sides)(height)
Area of 2 trapeziums
= 2[(1/2)(12)(10+20)] = 360 cm^2
Area of rectangle = base*height
Area of 4 rectangles
= 2[13 × 20] + 20(20) + 10(20) = 1120 cm^2
Total area = 1120 + 360 = 1480 cm^2
Option (C)
User avatar
S
hemantbafna
Manager
Manager
Joined: 30 Jan 2020
Posts: 167
Own Kudos [?]: 79 [0]
Given Kudos: 528
Location: India
WE:Accounting (Accounting)
Send PM
GMAT ToolKit User
The base of a vertical pillar with uniform cross section is a trapeziu [#permalink] New post   29 Oct 2020, 11:14
Can the experts explain the question in detail with the diagram, it is very confusing to imagine and understand.

Bunuel
avatar
B
BSTEPHANOS
Current Student
Joined: 09 Aug 2016
Posts: 8
Own Kudos [?]: 12 [2]
Given Kudos: 37
Send PM
Reviews Badge
The base of a vertical pillar with uniform cross section is a trapeziu [#permalink] New post   29 Oct 2020, 16:13
1
Kudos
1
Bookmarks
Quote:
The base of a vertical pillar with uniform cross section is a trapezium whose parallel sides are of lengths 10 cm and 20 cm while the other two sides are of equal length. The perpendicular distance between the parallel sides of the trapezium is 12 cm. If the height of the pillar is 20 cm, then the total area, in sq cm, of all six surfaces of the pillar is

A. 1300
B. 1340
C. 1480
D. 1520
E. 1580


hemantbafna
Hope the images clarify the form.

So Basically,
The question is asking for
Face1 + Face2 + Face3 + Face4 + Face5 + Face6
=400+200+260+260+180+180
=1480

Answer C
Attachments

1.PNG
1.PNG [ 100.83 KiB | Viewed 2769 times ]

2.PNG
2.PNG [ 66.04 KiB | Viewed 2750 times ]

3.PNG
3.PNG [ 59.56 KiB | Viewed 2756 times ]

4.PNG
4.PNG [ 69.68 KiB | Viewed 2746 times ]

User avatar
L
stne
SVP
SVP
Joined: 27 May 2012
Posts: 1682
Own Kudos [?]: 1431 [1]
Given Kudos: 633
Send PM
Re: The base of a vertical pillar with uniform cross section is a trapeziu [#permalink] New post   31 Oct 2020, 23:56
1
Kudos
BSTEPHANOS wrote:
Quote:
The base of a vertical pillar with uniform cross section is a trapezium whose parallel sides are of lengths 10 cm and 20 cm while the other two sides are of equal length. The perpendicular distance between the parallel sides of the trapezium is 12 cm. If the height of the pillar is 20 cm, then the total area, in sq cm, of all six surfaces of the pillar is

A. 1300
B. 1340
C. 1480
D. 1520
E. 1580


hemantbafna
Hope the images clarify the form.

So Basically,
The question is asking for
Face1 + Face2 + Face3 + Face4 + Face5 + Face6
=400+200+260+260+180+180
=1480

Answer C



Appreciate your hard work friend, awesome work on the figure!
User avatar
S
Hea234ven
Manager
Manager
Joined: 12 Jul 2019
Status:No knowledge goes waste
Posts: 73
Own Kudos [?]: 37 [0]
Given Kudos: 678
Location: Norway
Concentration: Finance, Economics
GPA: 3.3
WE:Corporate Finance (Commercial Banking)
Send PM
Re: The base of a vertical pillar with uniform cross section is a trapeziu [#permalink] New post   05 Nov 2020, 21:09
How did you get DE = 5?


Dillesh4096 wrote:
Bunuel wrote:
The base of a vertical pillar with uniform cross section is a trapezium whose parallel sides are of lengths 10 cm and 20 cm while the other two sides are of equal length. The perpendicular distance between the parallel sides of the trapezium is 12 cm. If the height of the pillar is 20 cm, then the total area, in sq cm, of all six surfaces of the pillar is

A. 1300
B. 1340
C. 1480
D. 1520
E. 1580


In the isosceles trapezium ABCD, ADE is a right angled triangle.
--> \(AD^2 = AE^2 + ED^2 = 12^2 + 5^2 = 169\)
--> \(AD = EC = 13\)

Note that all the sides of the trapezium forms 4 vertical walls of the pillar with height 20 cm and 2 horizontal surfaces with area as the area of trapezium

Area of vertical surfaces = \(10*20 + 13*20 + 13*20 + 20*20 = 56*20 = 1120\) sq.cm
Area of horizontal surfaces = \(2[\frac{1}{2}*(10 + 20)*12] = 30*12 = 360\) sq.cm

--> Total area = \(1120 + 360 = 1480\) sq. cm

Option C
GMAT Club Bot
gmatclubot
Re: The base of a vertical pillar with uniform cross section is a trapeziu [#permalink]
05 Nov 2020, 21:09
Moderators:
Bunuel
Math Expert
93035 posts
yashikaaggarwal
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne
Main navigation
GMAT Resources
Partners
MBA Resources
www.gmac.com|www.mba.com | | GMAT Club Rules | Terms and Conditions