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Bunuel
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Bunuel


The chart shows the water level in a reservoir over time. The vertical axis represents the water level, in meters, relative to the bottom of the reservoir. The horizontal axis represents the time, in minutes, since monitoring began.

The water level generally decreases as water is used for irrigation, but occasional rainfall causes the level to rise temporarily.

Select the option from each drop-down menu that creates the statement that most accurately reflects the information provided.

If the average rate of water level decrease monitored over the seven hours continues, the water level would reach zero after minutes.

The largest decrease in water level during any 30-minute interval shown on the graph was the largest increase during any 30-minute interval.
Attachment:
GMAT-Club-Forum-3tqqpjsn.png
The left point of the graph is at 120 metres and the right side is at 30 metres. So the decrease is (120-30)= 90 metres.

Using unitary method

90 metres needs 420 minutes , we need a drop of 30 metres to reach zero.

30 metres needs x minutes.

X = (420*30)/90

X = 140 minutes.

Question 2:

The largest decrease and largest increase during a 30 minute interval are :

Largest decrease = (105-75) = 30 metres. ( 120 - 150) minutes.

Largest Increase = (75 - 90) = 15 metres at (300 - 330) minutes.

30 = ————- * 15

30 = Twice * 15

Twice.
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We essentially have to calculate hourly average drop. For the same, let's first calculate individual drop numbers on a hourly basis. For eg: From 120 to 100 in first 60 minutes, the drop is -20
Thus we get the following values: -20, +5, -25, -10, +5, 0 and -40. Total hours is 7 hours
Average is sum of (-20+5-25-10+5+0-49)/7
This comes out to be approximately 12-13 meters.
Thus for 30 meters, rougly 2 and half hours or close to 140 minutes.


The largest decrease in water level during any 30-minute interval shown on the graph was the largest increase during any 30-minute interval.
Looking at larges increase which is from 75 to 105 which happens in 120 minutes to 150 minutes contributing 40% \(\frac{(105-75)}{75}\)*100=40%
Now the maximum increase have happened from 75 to 90 meters in 330 minutes which is 20% increase. Hence twice as much.
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Hi, Isn't the largest decrease actually at min.360 when it falls from 75 to approx 40 in 30 mins?

Thanks
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Hi, Isn't the largest decrease actually at min.360 when it falls from 75 to approx 40 in 30 mins?

Thanks
Replaced the graph. Thank you!
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