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# The ChildCare Center (CCC) is a medium-sized child care facility that

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Re: The ChildCare Center (CCC) is a medium-sized child care facility that [#permalink]
Bunuel -> kindly explain how to proceed in this question , In official answer the age of children changes on Friday of week 2 and i am unable to make out that how is the age changing as per attendance tab 3 chart ( WEEK 2 ATTENDANCE BY CLASS ROOM) ->?? kindly explain ....
or chetan2u whether you can explain...
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Re: The ChildCare Center (CCC) is a medium-sized child care facility that [#permalink]
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I would love an answer from an Expert too. I can't understand the OG's explanation at all.

However, here is how I solved the answer, and that was pretty simple. Hence the reason why I have doubts about my logic.

We are asked:"For each of the following classrooms, select More staff if more classroom staff members were assigned to that classroom on the Monday of Week 3 than on the Monday of Week 2. Otherwise, select Same/fewer staff"

We are told: "The classroom assignment and daily fee paid to CCC for each child are determined by the child's age on Friday of the previous week."

My understanding: we can assume that on the Monday of any week, we have the same number of child than on the previous Friday of that week.
==> The number of child on the Monday of Week 2 = the number of child on the Friday of Week 1
==> The number of child on the Monday of Week 3 = the number of child on the Friday of Week 2

Solve: therefore, we need to determine if the change in the number of child from Week 2 to Week 3 will have an impact on the required number of staff.
==> For the "TWOs" ==> Monday Week 2 = 9 and Friday Week 2 = 6 ==> Monday Week 3 will be 6 = Same/Few Staff
==> For the "THREEs" ==> Monday Week 2 = 15 and Friday Week 2 = 12 ==> Monday Week 3 will be 12 = Same/Few Staff
==> For the "FourFives" ==> Monday Week 2 = 12 and Friday Week 2 = 8 ==> Monday Week 3 will be 8 = Same/Few Staff

In essence, for all 3 groups we will have less kids on the Monday of Week 3 than on the Monday of Week 2. At this point, we don't care about the ratios of staff to children, we just know the required number of staff will be the same or less.

Hope this helps!
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Re: The ChildCare Center (CCC) is a medium-sized child care facility that [#permalink]
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I would love an answer from an Expert too. I can't understand the OG's explanation at all.

However, here is how I solved the answer, and that was pretty simple. Hence the reason why I have doubts about my logic.

We are asked:"For each of the following classrooms, select More staff if more classroom staff members were assigned to that classroom on the Monday of Week 3 than on the Monday of Week 2. Otherwise, select Same/fewer staff"

We are told: "The classroom assignment and daily fee paid to CCC for each child are determined by the child's age on Friday of the previous week."

My understanding: we can assume that on the Monday of any week, we have the same number of child than on the previous Friday of that week.
==> The number of child on the Monday of Week 2 = the number of child on the Friday of Week 1
==> The number of child on the Monday of Week 3 = the number of child on the Friday of Week 2

Solve: therefore, we need to determine if the change in the number of child from Week 2 to Week 3 will have an impact on the required number of staff.
==> For the "TWOs" ==> Monday Week 2 = 9 and Friday Week 2 = 6 ==> Monday Week 3 will be 6 = Same/Few Staff
==> For the "THREEs" ==> Monday Week 2 = 15 and Friday Week 2 = 12 ==> Monday Week 3 will be 12 = Same/Few Staff
==> For the "FourFives" ==> Monday Week 2 = 12 and Friday Week 2 = 8 ==> Monday Week 3 will be 8 = Same/Few Staff

In essence, for all 3 groups we will have less kids on the Monday of Week 3 than on the Monday of Week 2. At this point, we don't care about the ratios of staff to children, we just know the required number of staff will be the same or less.

Hope this helps!

abhimahna bro can you help in solving this ques.
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Re: The ChildCare Center (CCC) is a medium-sized child care facility that [#permalink]
sahilvijay wrote:
Strange enough, In my OG 2018 online edition -> i don't have this info there so i was unable to find how the birthdays are decided by official solution.

really?
can you take a screenshot? that's truly bizarre... since the questions SHOULD be pulled, in real time, from the same question pool on the wiley server. (when I set up the "quiz" again, this item showed up as no. 18 instead of no. 42.)
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Re: The ChildCare Center (CCC) is a medium-sized child care facility that [#permalink]
RonPurewal wrote:
sahilvijay wrote:
Strange enough, In my OG 2018 online edition -> i don't have this info there so i was unable to find how the birthdays are decided by official solution.

really?
can you take a screenshot? that's truly bizarre... since the questions SHOULD be pulled, in real time, from the same question pool on the wiley server. (when I set up the "quiz" again, this item showed up as no. 18 instead of no. 42.)

I just checked back online in OG 18 -> The lines you mentioned are now appearing, moreover i have pointed out some other mistakes in online OG (IR section) and sent mail to Wiley.
In November when i was solving and was unable to comprehend the solution (official solution) since this info was not added that time.
Also ditto question, which appeared to me in OG online is written in this forum above. And as you can see apart from myself there are 2 persons - one who posted the solution and other one who replied to his post were also unable to comprehend.

So i tagged you to explain me-> but after seeing this crucial info , which was not available to me I can understand the logic.

See the attachment -> this info is appearing now. It can be a technical issue possibly or they have corrected it.
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Untitled.jpeg [ 508.85 KiB | Viewed 17747 times ]

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Re: The ChildCare Center (CCC) is a medium-sized child care facility that [#permalink]
1
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Ahha it's possible that the copy-editing / quality-control person was just asleep (or drunk?) when this one came across his/her desk.
...because the second tab STILL says: "The ratio of the number of classroom staf in a particular classroom..."

so, it's not farfetched at all to suppose that the same editor simply failed to notice that a whole paragraph had gone missing from the earlier version. ?
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Re: The ChildCare Center (CCC) is a medium-sized child care facility that [#permalink]
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This online platform is a joke. I can't believe the OG platform would make such mistakes. The time and energy I expanded on this question (and the frustration lol), all that because of a missing paragraph XD

Posted from my mobile device
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Re: The ChildCare Center (CCC) is a medium-sized child care facility that [#permalink]
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This online platform is a joke. I can't believe the OG platform would make such mistakes. The time and energy I expanded on this question (and the frustration lol), all that because of a missing paragraph XD

Posted from my mobile device

you cant imagine how hard i struggled to even understand the OG 's explanation , which was going above my head due to missing text.
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Re: The ChildCare Center (CCC) is a medium-sized child care facility that [#permalink]
cxa0897 wrote:
OG explanations are notorious for being lack luster. As a general thought, Id recommend getting another source - Veritas, Magoosh, Manhattan etc to learn from, and then use the OG for drilling practice closer to the end of your preparation.

Regarding the question itself, you have to really dig into this to make sense of it. Staffing needs are determined on Friday of the week prior. We have to assume that the needs were met appropriately for Monday of week 2, and we can figure out how many staff members were on given the information in the Tab 2 chart. That gives you the base number for the problem.

Then, you can look at the information for Friday of week 2 to determine how many staff members are needed for the following Monday, and that will give you the delta that is asked for in the question.

To be honest though, I can follow their logic in the answer up until "C" and then I'm lost. There is a chance the OG is incorrect (wouldn't be the first time that happened) but I'm not sure. IR is kind of quirky, and there are a lot of questions with ambiguity in them. All in all, I don't recommend spending too much time trying to study for it, there are a lot of better uses of your time and the score is not weighed nearly as much as Q or V.

How about EA test, where IR is included in total score?
As for this question, I actually hate it because, because for IR 0020 according to official explanation they use the number of children on Monday for purposes of determining whether they need for staff taking into account birthdays, whereas on the next question (IR 0021) they use the number of children on Friday for determining whether the combination of classes would reduce the number of staff! In fact for one of the 3 option choices this difference gives a different outcome. I think it is mistake. Some of children have 3 days a week and most 5 days of week, so missing this information, it is not possible to assume which day of the week should be the basis, but why it should be a different day of the week then? There are generally more children on Monday than on Friday, so it seems like like some children miss Friday because of 3 day schedule, but it is just a guess. It is either IR 0021 or IR 0020 that must be wrong...
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Re: The ChildCare Center (CCC) is a medium-sized child care facility that [#permalink]
To further illustrate:
They say "There are many children who attend CCC every weekday, and a relatively small number attend fewer than 3 days per week"
It is not clear whether relatively small number can drive change in number of the staff or not, I assume yes, because we're talking about rounded numbers, even 12.1 makes it 13 for instance.
Now look at the table - there were 15 children on Monday and 16 on Tuesday and Thursday and only 12 children on Friday for the group of Threes. Why? They don't tell and this question does not include information on birthdays (unlike question IR 00020), so we must assume no birthday, ok, then it is reasonable to assume that 3 children had a day off on Friday! No other explanation is possible as they do not cite any other reasons. Fine, then contrary to the OG, we must use the figure of 16 children for the group of Three for calculation purpose, but the OG uses a figures of 12!
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Re: The ChildCare Center (CCC) is a medium-sized child care facility that [#permalink]
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Here is how I answered this question.

1. The CCC tab tells us that "There are many children who attend CCC every weekday, and a relatively small number attend fewer than 3 days per week."
So I used the true number of total enrollment which is the largest number of children enrolled in that class in that week (you could also presumably use the least amount of students each week but the point is to use the same baseline measure for the amounts to understand the overall ratio impact).

2.

2 children - Turned 1
1 child - Turned 2
1 child - Turned 3
4 children - Turned 4

3. Therefore: start with the week 2 numbers and find the week 3 numbers using the true (highest) number of students enrolled.

Infants: 11 - (2 children - Turned 1) = 9
Ones: 13 + (2 children - Turned 1) = 15 - (1 child - Turned 2) = 14
Twos: 10 + (1 child - Turned 2) = 11 - (1 child - Turned 3) = 10
Threes: 16 + (1 child - Turned 3) = 17 - (4 children - Turned 4) = 13
FoursFives: 12 + (4 children - Turned 4) = 16

So the Week 3 numbers are:
9, 14, 10, 13, 16.

4. Then, I simply looked at the old ratios and compared with the new ratios. From there I got the same answers as the OG: same, same, increase.
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The ChildCare Center (CCC) is a medium-sized child care facility that [#permalink]
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1. From the Saturday before Week 2 through the Friday of Week 2, exactly eight of the children in attendance at CCC had birthdays. Two children turned 1, one child turned 2, one child turned 3, and four children turned 4. All changes to classroom attendance from Week 2 to Week 3 were due to these birthdays.

For each of the following classrooms, select More staff if more classroom staff members were assigned to that classroom on the Monday of Week 3 than on the Monday of Week 2. Otherwise, select Same/fewer staff.

Monday of W2

- Age 2: 9 (<10) | Ratio 1:10 => Current staff are enough for 10

- Age 3: 15 (=13+3) | Ratio 1:13 => Current staff are enough for 26 (=2*13)

- Age 4-5: 12 (<13) | Ratio 1:13  => Current staff are enough for 13

Monday of W3

- Age 2: 9+1-1 = 9 (1 child turned 2 and 1 child turned 3) =>  Same/few staff

- Age 3: 15 + 1 - 4 = 12 (1 child turned 3 and 4 children turned 4) =>  Same/few staff

- Age 4 - 5: 12 + 4 = 16 (4 children turned 4) => More than 13 => More staff

2. In the Ones classroom in Week 2, for which one of the following days was the ratio of classroom staff to children least?
­
Ones: Min ratio: 1:4

The ratio is the least when exactly there is 1 teacher for every 4 children

=> The number of children on that day is divisble by 4

=> Thursday

3. Suppose that, in an effort to reduce staffing costs for the Friday of Week 2, the director of CCC had considered combining some classes for that day. For each of the following combinations, select Decrease if combining those classes would have decreased the number of classroom staff needed, provided that no other changes had occurred. Otherwise, select Increase/no change.

Infant, Ones:
- Infant: 9 children & Ratio: 1:4 => 3 teachers
- Ones: 10 children & Ratio: 1:4 => 3 teachers
- Combined: 9 + 10 = 19 => 5 teachers < 3 + 3
==> decrease

Ones, Twos
- Ones: 10 children & Ratio: 1:4 => 3 teachers
- Twos: 6 children & Ratio: 1:6 => 1 teacher
- Combined: 10 + 6 = 16 children & Ratio: 1:4 => 4 teachers = 3 + 1
=> Increase/no change

Threes, FourFives
- Threes: 12 chidren & Ratio: 1:10 => 2 teachers
- FoursFives: 8 children & Ratio: 1:13 => 1 teacher
- Combined: 12 + 8 = 20 children & Ratio: 1:10 => 2 teachers < 2 + 1
==> decrease­

Originally posted by Gemmie on 30 Mar 2024, 22:57.
Last edited by Gemmie on 25 Jun 2024, 21:34, edited 1 time in total.
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Re: The ChildCare Center (CCC) is a medium-sized child care facility that [#permalink]
For Q2,
In the Ones classroom, Minimum Ratio Staff:Children = 1:4
Monday 13 Kids => 4 Staff Staff:Children=4:13 (greater than 0.25)
Tuesday 13 Kids => 4 Staff Staff:Children=4:13 (greater than 0.25)
Wednesday 11 Kids => 3 Staff Staff:Children=3:11 (greater than 0.25)
Thursday 12 Kids => 3 Staff Staff:Children=3:12 (equal to 0.25)
Friday 10 Kids => 3 Staff Staff:Children=3:10 (greater than 0.25)­

Least Ratio is on Thursday
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Re: The ChildCare Center (CCC) is a medium-sized child care facility that [#permalink]
Gemmie wrote:
1. From the Saturday before Week 2 through the Friday of Week 2, exactly eight of the children in attendance at CCC had birthdays. Two children turned 1, one child turned 2, one child turned 3, and four children turned 4. All changes to classroom attendance from Week 2 to Week 3 were due to these birthdays.

For each of the following classrooms, select More staff if more classroom staff members were assigned to that classroom on the Monday of Week 3 than on the Monday of Week 2. Otherwise, select Same/fewer staff.

Monday of W2

- Age 2: 9 (<10) | Ratio 1:10 => Current staff are enough for 10

- Age 3: 15 (=13+3) | Ratio 1:13 => Current staff are enough for 26 (=2*13)

- Age 4-5: 12 (<13) | Ratio 1:13 => Current staff are enough for 13

Monday of W3

- Age 2: 9+1-1 = 9 (1 child turned 2 and 1 child turned 3) => Same/few staff

- Age 3: 15 + 1 - 4 = 12 (1 child turned 3 and 4 children turned 4) => Same/few staff

- Age 4 - 5: 12 + 4 = 16 (4 children turned 4) => More than 13 => More staff

2. In the Ones classroom in Week 2, for which one of the following days was the ratio of classroom staff to children least?
­
Ones: Min ratio: 1:4

The ratio is the least when exactly there is 1 teacher for every 4 children

=> The number of children on that day is divisble by 4

=> Thursday

3. Suppose that, in an effort to reduce staffing costs for the Friday of Week 2, the director of CCC had considered combining some classes for that day. For each of the following combinations, select Decrease if combining those classes would have decreased the number of classroom staff needed, provided that no other changes had occurred. Otherwise, select Increase/no change.

Infant, Ones:
- Infant: 9 children & Ratio: 1:4 => 3 teachers
- Ones: 10 children & Ratio: 1:4 => 3 teachers
- Combined: 9 + 10 = 19 => 5 teachers < 3 + 3
==> decrease

Ones, Twos
- Ones: 10 children & Ratio: 1:4 => 3 teachers
- Twos: 6 children & Ratio: 1:6 => 1 teacher
- Combined: 10 + 6 = 16 children & Ratio: 1:4 => 4 teachers = 3 + 1
=> Increase/no change

Threes, FourFives
- Threes: 12 chidren & Ratio: 1:10 => 2 teachers
- FoursFives: 8 children & Ratio: 1:13 => 1 teacher
- Combined: 12 + 8 = 20 children & Ratio: 1:10 => 2 teachers < 2 + 1
==> decrease­

­How are we sure that the 4 students who turned four will be added on Monday? 4 will be added to the total number of students but how can we determine on which day or days these students will be added?
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Re: The ChildCare Center (CCC) is a medium-sized child care facility that [#permalink]
"All changes to classroom attendance from Week 2 to Week 3 were due to these birthdays."
==> Therefore I suppose we can use the W2 enrollment as for W3 and proceed with the calculations
RishabhBhasin wrote:
Gemmie wrote:
1. From the Saturday before Week 2 through the Friday of Week 2, exactly eight of the children in attendance at CCC had birthdays. Two children turned 1, one child turned 2, one child turned 3, and four children turned 4. All changes to classroom attendance from Week 2 to Week 3 were due to these birthdays.

For each of the following classrooms, select More staff if more classroom staff members were assigned to that classroom on the Monday of Week 3 than on the Monday of Week 2. Otherwise, select Same/fewer staff.

Monday of W2

- Age 2: 9 (<10) | Ratio 1:10 => Current staff are enough for 10

- Age 3: 15 (=13+3) | Ratio 1:13 => Current staff are enough for 26 (=2*13)

- Age 4-5: 12 (<13) | Ratio 1:13 => Current staff are enough for 13

Monday of W3

- Age 2: 9+1-1 = 9 (1 child turned 2 and 1 child turned 3) => Same/few staff

- Age 3: 15 + 1 - 4 = 12 (1 child turned 3 and 4 children turned 4) => Same/few staff

- Age 4 - 5: 12 + 4 = 16 (4 children turned 4) => More than 13 => More staff

2. In the Ones classroom in Week 2, for which one of the following days was the ratio of classroom staff to children least?
­
Ones: Min ratio: 1:4

The ratio is the least when exactly there is 1 teacher for every 4 children

=> The number of children on that day is divisble by 4

=> Thursday

3. Suppose that, in an effort to reduce staffing costs for the Friday of Week 2, the director of CCC had considered combining some classes for that day. For each of the following combinations, select Decrease if combining those classes would have decreased the number of classroom staff needed, provided that no other changes had occurred. Otherwise, select Increase/no change.

Infant, Ones:
- Infant: 9 children & Ratio: 1:4 => 3 teachers
- Ones: 10 children & Ratio: 1:4 => 3 teachers
- Combined: 9 + 10 = 19 => 5 teachers < 3 + 3
==> decrease

Ones, Twos
- Ones: 10 children & Ratio: 1:4 => 3 teachers
- Twos: 6 children & Ratio: 1:6 => 1 teacher
- Combined: 10 + 6 = 16 children & Ratio: 1:4 => 4 teachers = 3 + 1
=> Increase/no change

Threes, FourFives
- Threes: 12 chidren & Ratio: 1:10 => 2 teachers
- FoursFives: 8 children & Ratio: 1:13 => 1 teacher
- Combined: 12 + 8 = 20 children & Ratio: 1:10 => 2 teachers < 2 + 1
==> decrease­

­How are we sure that the 4 students who turned four will be added on Monday? 4 will be added to the total number of students but how can we determine on which day or days these students will be added?

­
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