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The Coen family consists of a father, a mother, two children [#permalink]
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30 May 2012, 21:13
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The Coen family consists of a father, a mother, two children and a dog. A photographer is about to take the family's picture. How many different arrangements (of standing in a row) does the photographer have, if it is known that the father insists of standing by his woman, as the song says? A. 12 B. 24 C. 48 D. 60 E. 120 Bunuel your solution is required, thank you.
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Re: combinations [#permalink]
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30 May 2012, 22:32
4!*2= 48 (Father*Mother)*c1*c2*Dog



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Re: combinations [#permalink]
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30 May 2012, 22:35
BDSunDevil wrote: 4!*2= 48 (Father*Mother)*c1*c2*Dog hi thanks but please can you elaborate,in a more simpler manner, couldn't get it



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Re: The Coen family consists of a father, a mother, two children [#permalink]
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31 May 2012, 00:41
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Joy111 wrote: The Coen family consists of a father, a mother, two children and a dog. A photographer is about to take the family's picture. How many different arrangements (of standing in a row) does the photographer have, if it is known that the father insists of standing by his woman, as the song says?
A. 12 B. 24 C. 48 D. 60 E. 120
Bunuel your solution is required, thank you. We need to find the number of arrangements of Father, Mother, Child1, Child2, and a Dog, so that F and M are always together. Consider F and M to be one unit, then we would have total of four units: {FM}, {C1}, {C2}, {D}. The number of arrangements of these four units is 4!, but F and M within their unit can be arranged in 2 ways: {FM} or {MF}, so total number of arrangements is 4!*2=48. Answer: C. Hope it's clear.
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Re: The Coen family consists of a father, a mother, two children [#permalink]
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31 May 2012, 01:26
Bunuel wrote: Joy111 wrote: The Coen family consists of a father, a mother, two children and a dog. A photographer is about to take the family's picture. How many different arrangements (of standing in a row) does the photographer have, if it is known that the father insists of standing by his woman, as the song says?
A. 12 B. 24 C. 48 D. 60 E. 120
Bunuel your solution is required, thank you. We need to find the number of arrangements of Father, Mother, Child1, Child2, and a Dog, so that F and M are always together. Consider F and M to be one unit, then we would have total of four units: {FM}, {C1}, {C2}, {D}. The number of arrangements of these four units is 4!, but F and M within their unit can be arranged in 2 ways: {FM} or {MF}, so total number of arrangements is 4!*2=48. Answer: C. Hope it's clear. Bunuel thank you +1 , please can you show me the link to more similar questions, so that I can clear my concept



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Re: The Coen family consists of a father, a mother, two children [#permalink]
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06 Sep 2014, 04:54
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Joy111 wrote: The Coen family consists of a father, a mother, two children and a dog. A photographer is about to take the family's picture. How many different arrangements (of standing in a row) does the photographer have, if it is known that the father insists of standing by his woman, as the song says?
A. 12 B. 24 C. 48 D. 60 E. 120
Bunuel your solution is required, thank you. eeee.. got this question wrong.. just counted father & mother as an single entity but forget to count 2 possibility where they could be arranged by themselves.



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Re: The Coen family consists of a father, a mother, two children [#permalink]
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30 Jan 2016, 02:46
Hello, I don't understand why in this case we do not use the usual method: total arrangements  restrictions. For example, why in this case we can't solve it like this: 5!  4!*2 ?



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Re: The Coen family consists of a father, a mother, two children [#permalink]
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