It is currently 20 Nov 2017, 14:46

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Expert Post
1 KUDOS received
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 42269

Kudos [?]: 132826 [1], given: 12378

The coordinates of points A and B are p, q and (r, s). Is |q| > |s|? [#permalink]

Show Tags

New post 25 Jul 2017, 22:47
1
This post received
KUDOS
Expert's post
3
This post was
BOOKMARKED
00:00
A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

55% (00:55) correct 45% (01:18) wrong based on 107 sessions

HideShow timer Statistics

Kudos [?]: 132826 [1], given: 12378

2 KUDOS received
Director
Director
User avatar
G
Joined: 18 Aug 2016
Posts: 550

Kudos [?]: 161 [2], given: 134

GMAT 1: 630 Q47 V29
GMAT ToolKit User Premium Member Reviews Badge CAT Tests
Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|? [#permalink]

Show Tags

New post 26 Jul 2017, 04:30
2
This post received
KUDOS
3
This post was
BOOKMARKED
Bunuel wrote:
The coordinates of points A and B are (p, q) and (r, s). Is |q| > |s|?

(1) The points A and B are equidistant from the origin.
(2) |p| > |r|.


(1) Let the origin be O
\(OA = \sqrt{(p^2+q^2)}\)
\(OB = \sqrt{(r^2+s^2)}\)
OA = OB

Insufficient

(2) Absolute Value of p > Absolute Value of r
Insufficient

On combining
IF
\(\sqrt{(r^2+s^2)} = \sqrt{(p^2+q^2)}\)
& Absolute Value of p > Absolute Value of r
then
Absolute Value of q < Absolute Value of s
Sufficient
C
_________________

We must try to achieve the best within us


Thanks
Luckisnoexcuse

Kudos [?]: 161 [2], given: 134

Senior Manager
Senior Manager
avatar
B
Joined: 15 Jan 2017
Posts: 299

Kudos [?]: 21 [0], given: 681

Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|? [#permalink]

Show Tags

New post 28 Jul 2017, 11:31
C for me. Reasoning below:

is |q| > |s|?
so basically the value of q more than s.
st 1) p,q and r,s are equidistant. But we don't know the values. So, we don't know if |q| > |s|.Not suff

st 2) given |p| > |r|
Not suff. No clue as to what the values are

1) + 2) thus if they are equidistant and |p| > |r| so |q| > |s|.
Hope this is helpful.

Kudos [?]: 21 [0], given: 681

Manager
Manager
avatar
B
Joined: 19 Aug 2016
Posts: 60

Kudos [?]: 3 [0], given: 1

Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|? [#permalink]

Show Tags

New post 12 Oct 2017, 19:29
Bunuel wrote:
The coordinates of points A and B are (p, q) and (r, s). Is |q| > |s|?

(1) The points A and B are equidistant from the origin.
(2) |p| > |r|.


if the two points A and B are equidistant then lets say point A (0,4) and point B (4,0) then |q| >|s|?

Pls explain thanks

Kudos [?]: 3 [0], given: 1

Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?   [#permalink] 12 Oct 2017, 19:29
Display posts from previous: Sort by

The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.