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The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?

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Joined: 02 Sep 2009
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The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?  [#permalink]

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New post 25 Jul 2017, 22:47
1
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A
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C
D
E

Difficulty:

  55% (hard)

Question Stats:

54% (01:36) correct 46% (01:48) wrong based on 146 sessions

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Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?  [#permalink]

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New post 26 Jul 2017, 04:30
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Bunuel wrote:
The coordinates of points A and B are (p, q) and (r, s). Is |q| > |s|?

(1) The points A and B are equidistant from the origin.
(2) |p| > |r|.


(1) Let the origin be O
\(OA = \sqrt{(p^2+q^2)}\)
\(OB = \sqrt{(r^2+s^2)}\)
OA = OB

Insufficient

(2) Absolute Value of p > Absolute Value of r
Insufficient

On combining
IF
\(\sqrt{(r^2+s^2)} = \sqrt{(p^2+q^2)}\)
& Absolute Value of p > Absolute Value of r
then
Absolute Value of q < Absolute Value of s
Sufficient
C
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Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?  [#permalink]

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New post 28 Jul 2017, 11:31
C for me. Reasoning below:

is |q| > |s|?
so basically the value of q more than s.
st 1) p,q and r,s are equidistant. But we don't know the values. So, we don't know if |q| > |s|.Not suff

st 2) given |p| > |r|
Not suff. No clue as to what the values are

1) + 2) thus if they are equidistant and |p| > |r| so |q| > |s|.
Hope this is helpful.
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Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?  [#permalink]

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New post 12 Oct 2017, 19:29
Bunuel wrote:
The coordinates of points A and B are (p, q) and (r, s). Is |q| > |s|?

(1) The points A and B are equidistant from the origin.
(2) |p| > |r|.


if the two points A and B are equidistant then lets say point A (0,4) and point B (4,0) then |q| >|s|?

Pls explain thanks
GMAT Club Bot
Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|? &nbs [#permalink] 12 Oct 2017, 19:29
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