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Math Expert V
Joined: 02 Sep 2009
Posts: 61524
The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?  [#permalink]

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Difficulty:   55% (hard)

Question Stats: 54% (01:38) correct 46% (01:49) wrong based on 147 sessions

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The coordinates of points A and B are (p, q) and (r, s). Is |q| > |s|?

(1) The points A and B are equidistant from the origin.
(2) |p| > |r|.

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Joined: 18 Aug 2016
Posts: 590
Concentration: Strategy, Technology
GMAT 1: 630 Q47 V29 GMAT 2: 740 Q51 V38 Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?  [#permalink]

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Bunuel wrote:
The coordinates of points A and B are (p, q) and (r, s). Is |q| > |s|?

(1) The points A and B are equidistant from the origin.
(2) |p| > |r|.

(1) Let the origin be O
$$OA = \sqrt{(p^2+q^2)}$$
$$OB = \sqrt{(r^2+s^2)}$$
OA = OB

Insufficient

(2) Absolute Value of p > Absolute Value of r
Insufficient

On combining
IF
$$\sqrt{(r^2+s^2)} = \sqrt{(p^2+q^2)}$$
& Absolute Value of p > Absolute Value of r
then
Absolute Value of q < Absolute Value of s
Sufficient
C
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##### General Discussion
Senior Manager  S
Joined: 15 Jan 2017
Posts: 319
Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?  [#permalink]

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C for me. Reasoning below:

is |q| > |s|?
so basically the value of q more than s.
st 1) p,q and r,s are equidistant. But we don't know the values. So, we don't know if |q| > |s|.Not suff

st 2) given |p| > |r|
Not suff. No clue as to what the values are

1) + 2) thus if they are equidistant and |p| > |r| so |q| > |s|.
Manager  B
Joined: 19 Aug 2016
Posts: 70
Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?  [#permalink]

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Bunuel wrote:
The coordinates of points A and B are (p, q) and (r, s). Is |q| > |s|?

(1) The points A and B are equidistant from the origin.
(2) |p| > |r|.

if the two points A and B are equidistant then lets say point A (0,4) and point B (4,0) then |q| >|s|?

Pls explain thanks
CrackVerbal Quant Expert G
Joined: 12 Apr 2019
Posts: 400
Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?  [#permalink]

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We have two points A(p,q) and B(r,s) on the co-ordinate plane. Note that these points can be in any of the four quadrants and hence pay due attention to the signs of the co-ordinates as well.

In the question, we are trying to find if the absolute value of q is more than the absolute value of s.

Statement II alone does not give us any information about the question we are trying to answer, since it only talks about p and r. Therefore, let us eliminate options B and D since statement II alone is insufficient.
The possible answer options at this stage are A, C or E.

From statement I alone, we only know that the two points are equidistant from the origin.

If we take A(3,4) and B(4,3), both points are equidistant from the origin. In this case q = 4 and s = 3 and hence |q| > |s|.

If we take A(1,1) and B(-1,-1), both points are equidistant from the origin, but |q| = |s|.

Statement I alone is insufficient. Answer option A can be eliminated, possible answer options are C or E.

Combining statements I and II, we know that A and B are equidistant from the origin, and |p| > |r|.

Since A and B are equidistant from the origin, $$p^2 + q^2 = r^2 + s^2$$. Also, distance of p from ZERO on x-axis is higher than the distance of r from ZERO on the x-axis (remember that p and r are the x co-ordinates).
If the equation above has to be satisfied, then distance of q from ZERO on y-axis should be lower than the distance of s from ZERO on y-axis. This is to balance out the equation. Otherwise, the LHS would become greater than the RHS.

Another easy way of understanding this concept is by looking at co-ordinates like (4,3) and (3,4). Here since |p|>|r|, you can observe that |q|<|s|. If you take the case of (1,1) and (-1,-1), you see that |p| = |r| and hence it turns out that |q| = |s| so that the equation holds.

The combination of statements is sufficient to say |q| < |s| and answer the question with a definite NO. Answer option E can be eliminated.
The correct answer option is C.

Hope that helps!
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Posts: 400
Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?  [#permalink]

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zanaik89 wrote:
Bunuel wrote:
The coordinates of points A and B are (p, q) and (r, s). Is |q| > |s|?

(1) The points A and B are equidistant from the origin.
(2) |p| > |r|.

if the two points A and B are equidistant then lets say point A (0,4) and point B (4,0) then |q| >|s|?

Pls explain thanks

Hello Zanaik,

You cannot prove or disprove a statement based on one set of values alone. What if we take points A(4,3) and B(3,4)? These are equidistant from the origin as well. Here |q| < |s|. If you swap the co-ordinates, you will also be able to obtain |q| > |s|.

If you take (1,1) and (-1,-1), you will be able to obtain |q| = |s| also.

And that is WHY, statement I alone is insufficient. So, it's not about proving that |q| > |s|, you are better off disproving it to prove that the statement is insufficient.

Hope that helps!
_________________ Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?   [#permalink] 29 Nov 2019, 01:11
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