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The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?

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The coordinates of points A and B are p, q and (r, s). Is |q| > |s|? [#permalink]

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25 Jul 2017, 21:47
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The coordinates of points A and B are (p, q) and (r, s). Is |q| > |s|?

(1) The points A and B are equidistant from the origin.
(2) |p| > |r|.
[Reveal] Spoiler: OA

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Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|? [#permalink]

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26 Jul 2017, 03:30
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Bunuel wrote:
The coordinates of points A and B are (p, q) and (r, s). Is |q| > |s|?

(1) The points A and B are equidistant from the origin.
(2) |p| > |r|.

(1) Let the origin be O
$$OA = \sqrt{(p^2+q^2)}$$
$$OB = \sqrt{(r^2+s^2)}$$
OA = OB

Insufficient

(2) Absolute Value of p > Absolute Value of r
Insufficient

On combining
IF
$$\sqrt{(r^2+s^2)} = \sqrt{(p^2+q^2)}$$
& Absolute Value of p > Absolute Value of r
then
Absolute Value of q < Absolute Value of s
Sufficient
C
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Joined: 15 Jan 2017
Posts: 359
Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|? [#permalink]

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28 Jul 2017, 10:31
C for me. Reasoning below:

is |q| > |s|?
so basically the value of q more than s.
st 1) p,q and r,s are equidistant. But we don't know the values. So, we don't know if |q| > |s|.Not suff

st 2) given |p| > |r|
Not suff. No clue as to what the values are

1) + 2) thus if they are equidistant and |p| > |r| so |q| > |s|.
Hope this is helpful.
Manager
Joined: 19 Aug 2016
Posts: 72
Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|? [#permalink]

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12 Oct 2017, 18:29
Bunuel wrote:
The coordinates of points A and B are (p, q) and (r, s). Is |q| > |s|?

(1) The points A and B are equidistant from the origin.
(2) |p| > |r|.

if the two points A and B are equidistant then lets say point A (0,4) and point B (4,0) then |q| >|s|?

Pls explain thanks
Re: The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?   [#permalink] 12 Oct 2017, 18:29
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The coordinates of points A and B are p, q and (r, s). Is |q| > |s|?

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