The distance from the lake to a tree spans 0.02 kilometers

Question

The distance from the lake to a tree spans 0.02 kilometers, and a snail has already covered a distance of 0.8 meters. How many times longer is the remaining distance for the snail compared to the distance it has already covered?

A. 1.5
B. 24
C. 25
D. 249
E. 2,499

A. 1.5
B. 24
C. 25
D. 249
E. 2,499

Bunuel · Accepted Answer

Official Solution:

The distance from the lake to a tree spans 0.02 kilometers, and a snail has already covered a distance of 0.8 meters. How many times longer is the remaining distance for the snail compared to the distance it has already covered?

A. 1.5
B. 24
C. 25
D. 249
E. 2,499

A. 1.5
B. 24
C. 25
D. 249
E. 2,499

0.02 kilometers equals 0.02 * 1,000 = 20 meters.

0.8 meters constitutes 4% of 20 meters. Consequently, the snail has traversed 4% of the distance, leaving 96% yet to cover. Thus, the remaining distance is  \frac{96}{4}=24  times longer than the distance it has already covered.

Answer: B

Abhishek009 · Answer

1 Km = 1000 m 
Distance from the lake to a tree = 20 Meters

Snail has already covered a distance of 0.8 meters.

Distance left is 20 - 0.80 = 19.20 meters
 
 \frac{19.20}{0.80} = 24 , Answer will be (B) 24

GMATBusters · Answer

The distance from the lake to the tree is 0.02 km = 20 meters.

Distance covered = 0.8m

Remaining distance = Total distance - Distance covered= 20 m - 0.8m = 19.2m

Times longer = Remaining distance / Distance covered= 9.2/0.8 = 24

Answer = B

Another Approach:

It can be done like this : total distance = 20m
already covered = 0.8m

Distance is 20/0.8 = 25 times the total distance
so, remaining distance = 25-1 = 24 times (B)

kopp74 · Answer

Check out this method.

0.2km = 20 meters
Distance passed by the snake = 0.8 m.

20-.8 = 19.2 = distance remainig

We have to find how many times is 0.8 equal to19.2, in other words , 0.8 * (d) = 19.2
We can eliminate all choices and try with 24 and 25 as they are the closest to 19.2

24 * 0.8 =24 - 24*(0.2) = 24 - 2.4*2 = 19.2  ->  B accepted

Option B

I hope it could simplify the process and calculations for you

Please, let me know if you think there is anything wrong

gmatophobia · Answer

Assume that the speed of the snail is 0.8 m/sec

Hence, the snail covered a distance of 0.8 meters in 1 sec.

Time the snail would take to cover 0.02 kilometers =  \frac{0.02 * 1000 }{ 0.8} = 25  seconds

Remaining time = 25 - 1 = 24 seconds

Option B

Sid7210 · Answer

0.02 KM=20 meters,
the snail has travelled 0.8 meters ,so that leaves 19.2 meters to be travelled.
this problem can also be done by slight approximation
if the snail had travelled 1m so far the remaining distance would have been 19.2 times the distance
But since it is less than 1m, the answer will be only slightly more than 19.2, this eliminates options A,D AND E and 
25*8 = 200 so 25*0.8 is 20 so we are left with options B that is the answer.

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The distance from the lake to a tree spans 0.02 kilometers

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