Quote:
The prompt says: The exponent of axax is a multiple of 20
xx must be a positive integer. The first positive multiple of 20 is 20.
How can x=10x=10?
the whole exponent is a multiple of 20 , not x
and i put
a^x = 20 . y (20 is a factor of a^x ) (and y is what ever the rest of a^x could be )
a^x = 2^2 . 5 . y
now i want to start trying values for a
can a be 2 for example ? no
why ? because 2^(what ever ) will produce a number that only has 2s as factors . I want to produce a number that has both 2s and at least one 5 as factors .
can a be 3 ? no for the same reason , also a cannot be 4,5,6,7,8,9
now we reach 10 .
a can be 10 , yes we can produce a number that has both 2s and 5 when raised to a power .
but what power of 10 ? we are interested in the least possible value .
if a=10
and x=a.k ( a is a factor of x )
then x is at least 10
so a^x =10^10
and that is a multiple of 20