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61.24 x (0.998) 2 403 The expression above is approximately equal to

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Bunuel
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61.24 x (0.998) 2 403 The expression above is approximately equal to [#permalink] New post  19 Jan 2014, 23:47
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\(\frac{61.24*0.998^2}{\sqrt{403}}\)
The expression above is approximately equal to

(A) 1
(B) 3
(C) 4
(D) 5
(E) 6
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Bunuel
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Re: 61.24 x (0.998) 2 403 The expression above is approximately equal to [#permalink] New post  19 Jan 2014, 23:47
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SOLUTION

\(\frac{61.24*0.998^2}{\sqrt{403}}\)
The expression above is approximately equal to

(A) 1
(B) 3
(C) 4
(D) 5
(E) 6

\(\frac{61.24*0.998^2}{\sqrt{403}}\approx{\frac{60*1}{\sqrt{400}}}=\frac{60}{20}=3\).

Answer: B.
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Re: 61.24 x (0.998) 2 403 The expression above is approximately equal to [#permalink] New post  20 Jan 2014, 02:19
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Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

\(\frac{61.24*0.998^2}{\sqrt{403}}\)
The expression above is approximately equal to

(A) 1
(B) 3
(C) 4
(D) 5
(E) 6

Problem Solving
Question: 47
Category: Arithmetic Operations on radical expressions
Page: 67
Difficulty: 650


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it is all about approximations

the numerator 61.24*.998^2=60(approximately)
the denominator sqrt(403)= 20(approximately)

hence the value of given expression is 3.

since the accurate value is not asked, it is ok to roughly approximate the values to quickly arrive at the correct answer
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Re: 61.24 x (0.998) 2 403 The expression above is approximately equal to [#permalink] New post  20 Jan 2014, 20:35
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Kudos
Here the key is APPROXIMATION .

0.998~1 ----> 1^2 = 1
403^1/2=20.07.... ~20

So after approximation our expression becomes - (61.24*1)/20 =3.06... ~ 3

So correct answer is (B)
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Re: 61.24 x (0.998) 2 403 The expression above is approximately equal to [#permalink] New post  20 Jan 2014, 21:14
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Kudos
Here, it would be advisable to look at the answer choices first. Since we have small integers, it will be easier if you can approx. the values to the closest integer.

0.998 ~ 1
\sqrt{403} ~ 20
Now, since we have 20 in the denominator and the answer choices are plain integers, 61.24 can be approximated to 60, thereby giving us a value of 3.

Ans is (B)
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Re: 61.24 x (0.998) 2 403 The expression above is approximately equal to [#permalink] New post  23 Jan 2014, 05:59
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Bunuel wrote:
\(\frac{61.24*0.998^2}{\sqrt{403}}\)
The expression above is approximately equal to

(A) 1
(B) 3
(C) 4
(D) 5
(E) 6



Since the question is asking for an approximate value hence the question can we written as

\(\frac{61.24*1^2}{\sqrt{400}}\)

\(= \frac{61.24*1^2}{20}= \frac{6124}{2000}=3\)



Answer B
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Re: 61.24 x (0.998) 2 403 The expression above is approximately equal to [#permalink] New post  25 Jan 2014, 11:38
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SOLUTION

\(\frac{61.24*0.998^2}{\sqrt{403}}\)
The expression above is approximately equal to

(A) 1
(B) 3
(C) 4
(D) 5
(E) 6

\(\frac{61.24*0.998^2}{\sqrt{403}}\approx{\frac{60*1}{\sqrt{400}}}=\frac{60}{20}=3\).

Answer: B.
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Re: 61.24 x (0.998) 2 403 The expression above is approximately equal to [#permalink] New post  29 Nov 2016, 13:45
Nice Official Question.
Here is what i did =>
Rounding up both the numerators to the nearest integer and the denominator to the nearest tenths.
We get =>\(\frac{60*1^2}{√400}\)
=> 6/2 => 3

Hence B
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