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Sub 505 Level|   Geometry|               
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Solution


Steps 1 & 2: Understand Question and Draw Inferences
In this question, we are given:
    • A figure having a piece of cheese from which a corner has been cut off.
    • The removed corner exposes the plane surface ABC.

We need to determine:
    • The area of the surface ABC.

The surface ABC is in the shape of a triangle.
    • Therefore, to find the area of ABC, we either need the length of all the 3 sides or length of 2 sides and angle between them.

With this understanding, let us now analyse the individual statements.

Step 3: Analyse Statement 1
“AD = 10 centimetres”

From this statement, we cannot determine any information about the length of sides of the triangle.
Hence, statement 1 is not sufficient to answer the question.

Step 4: Analyse Statement 2
“The shape of the cheese was a cube before the corner was cut off”
    • From this statement, we can say that length of sides of the triangle are the face diagonals of the cube.
    • And, all the diagonals will be of the equal length
    Hence, ABC is an equilateral triangle.

However, we cannot determine any information about the length of sides of the triangle.
Hence, statement 2 is not sufficient to answer the question.

Step 5: Combine Both Statements Together (If Needed)
From Statement 1:
    • AD = 10 cm
From Statement 2:
    • The length of sides of the triangle are the face diagonals of the cube.
    • ABC is an equilateral triangle.

Combining both the statements:
    • Side of the cube = 10 cm
    • Length of face diagonal of the cube = √(〖10〗^2+〖10〗^2 ) = 10√2 cm.

Now, we know the length of the side of the equilateral triangle. We can easily find the area of the surface ABC.
Since we could find the answer by combining both the statements, option C is the correct answer.

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Hi! Nowhere is it mentioned if its a cube or a rectangular solid...how is it safe to assume that the figure above is a cube?
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Hi! Nowhere is it mentioned if its a cube or a rectangular solid...how is it safe to assume that the figure above is a cube?

You are right the question stem does not say the figure is a cube and that is why we are not assuming it to be a cube.
If it were given that the figure is a cube then statement 1 alone would have been sufficient.
BUT,
Read statement 2 it says "The shape of the cheese was a cube before the corner was cut off."
This statement tells us that it is a cube, so we are not assuming anything now. However, this statement does not give us any value, making it INSUFF.

When combined, they yield the answer.
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How can we assume ABC are vertices?
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How can we assume ABC are vertices?
We are not assuming anything. It is literally given in the figure.
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Bunuel

The figure above shows a piece of cheese with a corner cut off to expose plane surface ABC. What is the area of surface ABC ?

(1) AD = 10 centimeters
(2) The shape of the cheese was a cube before the corner was cut off.

Attachment:
2019-04-26_1844.png


(1) We don't know about the nature of the shape; Insufficient.

(2) We don't the size of any sides of the cube. Insufficient.

Considering Both:
The surface an equilateral triangle with the corners of the cube. Corner of a cube\(=\sqrt{S}\) Sufficient.

The answer is \(C\)
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Hi, would anyone explain why the second graph (shown below) is not possible considering the information given?

If we consider the second graph possible, then the area of the shaded region can't be determined. Since it is not mention that AD or BE are vertical lines, I think that the second graph is possible.

Initial cheese keeps the form of a cube, what i'm changing is the axis AB since I don't find any restriction to do so.

Bunuel , DavidTutorexamPAL , EgmatQuantExpert chetan2u , Sajjad1994
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The figure above shows a piece of cheese.png
The figure above shows a piece of cheese.png [ 21.38 KiB | Viewed 9488 times ]

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Bunuel

The figure above shows a piece of cheese with a corner cut off to expose plane surface ABC. What is the area of surface ABC ?

(1) AD = 10 centimeters
(2) The shape of the cheese was a cube before the corner was cut off.


DS80602.01
Quantitative Review 2020 NEW QUESTION


Attachment:
2019-04-26_1844.png

Silly Question, but I havent understood how is it implied that the triangle is an equilateral triangle, based on the fact that the the cheese is a cube.

Could you pls explain? Bunuel VeritasKarishma
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Bunuel

The figure above shows a piece of cheese with a corner cut off to expose plane surface ABC. What is the area of surface ABC ?

(1) AD = 10 centimeters
(2) The shape of the cheese was a cube before the corner was cut off.


DS80602.01
Quantitative Review 2020 NEW QUESTION


Attachment:
2019-04-26_1844.png

Silly Question, but I havent understood how is it implied that the triangle is an equilateral triangle, based on the fact that the the cheese is a cube.

Could you pls explain? Bunuel VeritasKarishma

AB, BC and AC are diagonals of three equal faces (squares), so AB = BC = AC.

Does this make sense?
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Bunuel
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Bunuel

The figure above shows a piece of cheese with a corner cut off to expose plane surface ABC. What is the area of surface ABC ?

(1) AD = 10 centimeters
(2) The shape of the cheese was a cube before the corner was cut off.


DS80602.01
Quantitative Review 2020 NEW QUESTION


Attachment:
2019-04-26_1844.png

Silly Question, but I havent understood how is it implied that the triangle is an equilateral triangle, based on the fact that the the cheese is a cube.

Could you pls explain? Bunuel VeritasKarishma

AB, BC and AC are diagonals of three equal faces (squares), so AB = BC = AC.

Does this make sense?

OH RIGHT! Totally missed that. Thanks a lot!
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Bunuel
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Bunuel

The figure above shows a piece of cheese with a corner cut off to expose plane surface ABC. What is the area of surface ABC ?

(1) AD = 10 centimeters
(2) The shape of the cheese was a cube before the corner was cut off.


DS80602.01
Quantitative Review 2020 NEW QUESTION


Attachment:
2019-04-26_1844.png

Silly Question, but I havent understood how is it implied that the triangle is an equilateral triangle, based on the fact that the the cheese is a cube.

Could you pls explain? Bunuel VeritasKarishma

AB, BC and AC are diagonals of three equal faces (squares), so AB = BC = AC.

Does this make sense?

Unfortunately, I still do not get this. Can't they still be diagonals of the equal faces and let's say the cut takes more out of one side of the triangle than the others? egmat
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