Bunuel wrote:
The figure above shows Line L, Circle 1 with center at C1, and Circle 2 with center at C2. Line L intersects Circle 1 at points A and B, Line L intersects Circle 2 at points D and E, and points C1 and C2 are equidistant from line L. Is the area of ΔABC1 less than the area of ΔDEC2 ?
(1) The radius of Circle 1 is less than the radius of Circle 2.
(2) The length of chord AB is less than the length of chord DE.
Question stem:- Is the area of ΔABC1 less than the area of ΔDEC2 ?
Or, Is \(\frac{1}{2}*AB*h<\frac{1}{2}*DE*h\) ? (points C1 and C2 are equidistant from line L)
Or, Is AB<DE ?
St1:- \((C_{1}A=C_{1}B)< (C_{2}D=C_{2}E)\)
As points C1 and C2 are equidistant from line L; \(C_{1}H_{1}=C_{2}H_{2}\)
So AB<DE (3rd side of the triangle) (Figure enclosed)
Sufficient
St2:- AB<DE
Sufficient.
Ans. (D)
Attachments
Area triangle.JPG [ 27.67 KiB | Viewed 1897 times ]
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PKN
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60% (01:41) correct 
