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21 Jun 2019, 00:31
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
44% (02:45) correct
56%
(03:02)
wrong
based on 68
sessions
History
Date
Time
Result
Not Attempted Yet
The figure above shows the shape and dimensions of a floor that is to be carpeted. The desired carpet costs $30 per running meter, comes on a roll 6 meters wide, and has a finished surface on only one side. If AC=12 meters and if the only seam that is permitted is along the line through B and D, how much will the carpet cost?
A. $360
B. $390
C. $480
D. $540
E. $780
Attachment:
d1.JPG [ 3.95 KiB | Viewed 3393 times ]
21 Jun 2019, 04:20
Kudos
Bookmarks
Bunuel
6m wide roll will cost 30$ per running meter = 1 meter length
--> to cover an area of 6*1 = 6 m^2, cost = 30 $
The figure is divided into a rectangle ACGF and an isosceles triangle DFG
E is the midpoints of base FG with FE = EG = 12/2 = 6
We know that triangle DEF is right angled
--> DF^2 = DE^2 + FE^2
--> 10^2 = DE^2 + 6^2
--> DE^2 = 100 - 64 = 36
--> DE = 6 m
The carpet will run from AC (12 meters wide) till point D
Height of roll, DB = DE + EB = 8 + 5 = 13
per running meter of roll i.e 1 meter = 30$
For 13 meter running, Cost = 13*30 = 390 $
2 rolls are required to cover (running from AB & BC) = 780 $
IMO Option E
Pls Hit Kudos if you like the solution
Attachments
34.png [ 6.3 KiB | Viewed 3668 times ]
21 Jun 2019, 13:38
Kudos
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Dillesh4096
Hello Dillesh4096
Why if the uper part is a iscoceles triangle we are not using 1 : 1 : root2?
Kind regards!
