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# The first floor of a building is partitioned into four rectangular roo

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Re: The first floor of a building is partitioned into four rectangular roo [#permalink]
The perimeter of each rectangular room consists of $$2(l+w)$$

Out of each $$2(l+w)$$, $$(l+w)$$ is part of the larger rectangle.

Therefore to find the perimeter of the larger triangle, we need to divide each smaller rectangle perimeter by 2 and add them up:

$$60 + 140 + 100 + 80 = \frac{380 }{ 2} = 190$$

Answer is D.
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The first floor of a building is partitioned into four rectangular roo [#permalink]
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FOR SUCH QUESTION, SEE HOW MANY TIMES IS THE PERIMETER INCLUDED IN THE GIVEN THE FIGURE.

HERE IF YOU SEE CLEARLY, YOU WILL FIND THAT 1/2 OF EACH ROOM'S PERIMETER GIVES A PART OF PERIMETER ASKED FOR.

HENCE, YOU WILL:
1/2 THE PERIMETER OF THE 1ST ROOM +
1/2 PERIMIEERT OF THE 2ND ROOM +
1/2 PERIMETER OF 3RD ROOM +
1/2 PERIMETER OF THE 4TH ROOM TO GET THE FINAL PERIMETER OF THE FLOOR.

official answer:E
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Re: The first floor of a building is partitioned into four rectangular roo [#permalink]
Bunuel

The first floor of a building is partitioned into four rectangular rooms I, II, III, and IV, as shown in the figure above, with perimeters 60, 140, 100, and 80 meters, respectively. Assuming that the widths of the walls are negligible, what is the perimeter in meters of the first floor QRST ?

A. 760
B. 400
C. 380
D. 200
E. 190

PS20439

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30+40+50+70= 190

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Re: The first floor of a building is partitioned into four rectangular roo [#permalink]
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