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14 Aug 2023, 06:00
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
85% (01:49) correct
15%
(02:05)
wrong
based on 774
sessions
History
Date
Time
Result
Not Attempted Yet
Step 1: Multiply x by 3.
Step 2: Take the square root of the result of step 1.
Step 3: Take the reciprocal of the result of step 2.
Step 4: Add 1 to the result of step 3.
Step 5: Square the result of step 4.
The five steps shown will result in an expression equivalent to which of the following?
A. \(\frac{1 + 3x}{3x}\)
B. \(\frac{1 + 9x}{9x}\)
C. \(\frac{1}{3x + 3\sqrt{3x} +1}\)
D. \(\frac{1 + 2\sqrt{3x} +3x}{3x}\)
E. \(\frac{1 + 6\sqrt{x} +9x}{9x}\)
Step 2: Take the square root of the result of step 1.
Step 3: Take the reciprocal of the result of step 2.
Step 4: Add 1 to the result of step 3.
Step 5: Square the result of step 4.
The five steps shown will result in an expression equivalent to which of the following?
A. \(\frac{1 + 3x}{3x}\)
B. \(\frac{1 + 9x}{9x}\)
C. \(\frac{1}{3x + 3\sqrt{3x} +1}\)
D. \(\frac{1 + 2\sqrt{3x} +3x}{3x}\)
E. \(\frac{1 + 6\sqrt{x} +9x}{9x}\)
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14 Aug 2023, 06:36
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The five steps shown will result in an expression equivalent to which of the following?
Step 1: Multiply x by 3.
\(3x\)
Step 2: Take the square root of the result of step 1.
\(\sqrt{3x}\)
Step 3: Take the reciprocal of the result of step 2.
\(\frac{1}{\sqrt{3x}\)
Step 4: Add 1 to the result of step 3.
\(\frac{1}{\sqrt{3x}} + 1 = \frac{1 + \sqrt{3x}}{\sqrt{3x}}\)
Step 5: Square the result of step 4.
\(\frac{1 + 2\sqrt{3x} +3x}{3x}\)
The correct answer is (D).
Step 1: Multiply x by 3.
\(3x\)
Step 2: Take the square root of the result of step 1.
\(\sqrt{3x}\)
Step 3: Take the reciprocal of the result of step 2.
\(\frac{1}{\sqrt{3x}\)
Step 4: Add 1 to the result of step 3.
\(\frac{1}{\sqrt{3x}} + 1 = \frac{1 + \sqrt{3x}}{\sqrt{3x}}\)
Step 5: Square the result of step 4.
\(\frac{1 + 2\sqrt{3x} +3x}{3x}\)
The correct answer is (D).
14 Aug 2023, 06:32
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Bunuel
Very different than the traditional questions
Step 1: Multiply x by 3.
Result: \(3*x\)
Step 2: Take the square root of the result of step 1.
Result: \(\sqrt{3*x}\)
Step 3: Take the reciprocal of the result of step 2.
Result: \(\frac{1}{\sqrt{3*x}}\)
Step 4: Add 1 to the result of step 3.
Result: \(\frac{1}{\sqrt{3*x}}+1\)
Step 5: Square the result of step 4.
Result: \((\frac{1}{\sqrt{3*x}}+1)^2\)
\((\frac{1}{\sqrt{3*x}})^2 + 1^2 + 2*(\frac{1}{\sqrt{3*x}})\)
\(\frac{1}{3x} + 1 + \frac{2}{\sqrt{3x}}\)
Take \(3x\) as LCM
\(\frac{1 + 3x + 2\sqrt{3x}}{3x}\)
Option D
