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\(x\): 9
\(y\): 3
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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The function \(f(x,y)\) is such that \(f(x,y) = \frac{(3x + 7y)}{(x+y)}\), where \(x+y\neq{0}\).
In the table, select a value for x and a value for y corresponding to \(f(x,y) = 4\). Make only two selections, one in each column.
In the table, select a value for x and a value for y corresponding to \(f(x,y) = 4\). Make only two selections, one in each column.
| \(x\) | \(y\) | Values |
| 3 | ||
| 5 | ||
| 7 | ||
| 9 | ||
| 12 |
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Official Answer
\(x\): 9
\(y\): 3
arpanpatnaik
GMAT 1: 640 Q42 V37
Posts: 101
Updated on: 09 May 2013, 03:16
Originally posted by arpanpatnaik on 07 May 2013, 10:36.
Last edited by arpanpatnaik on 09 May 2013, 03:16, edited 1 time in total.
Last edited by arpanpatnaik on 09 May 2013, 03:16, edited 1 time in total.
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For the above expression:
f(x,y) = 3x+7y/x+y, where x+y != 0, if the value of f(x,y) = 4, the expression can be reduced to:
f(x,y) = 4 = 3x+7y/x+y
=> x = 7y - 4y
=> x = 3y
From the table of values given I am assuming we are to select two values which are fit the equation f(x,y).
The only values which match the above condition are 3 and 9. Hence f(9,3) = 4. **edited as rajmatthew pointed out. Thanks Raj!
Please correct me if I am wrong!
Regards,
Arpan
f(x,y) = 3x+7y/x+y, where x+y != 0, if the value of f(x,y) = 4, the expression can be reduced to:
f(x,y) = 4 = 3x+7y/x+y
=> x = 7y - 4y
=> x = 3y
From the table of values given I am assuming we are to select two values which are fit the equation f(x,y).
Bunuel
The only values which match the above condition are 3 and 9. Hence f(9,3) = 4. **edited as rajmatthew pointed out. Thanks Raj!
Please correct me if I am wrong!
Regards,
Arpan
