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13 Mar 2020, 22:28
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
50% (01:52) correct
50%
(01:55)
wrong
based on 116
sessions
History
Date
Time
Result
Not Attempted Yet
The function {\(x\)} is defined as the lowest integer greater than or equal to \(x\). What is the value of {\(x\)}, if \(x\) is negative?
1. -3.1 ≤ \(x\) ≤ -2.5
2. \(x^2\) ≤ 4
1. -3.1 ≤ \(x\) ≤ -2.5
2. \(x^2\) ≤ 4
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13 Mar 2020, 22:40
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rheam25
Statement 1: -3.1 ≤ \(x\) ≤ -2.5
If x = -3.5, the {x} = -3
If x = -2.5, the {x} = -2
NOT SUFFICIENT
Statement 2: \(x^2\) ≤ 4
I.e. -2 ≤ x ≤ 2
If x = -2, the {x} = -2
If x = -1, the {x} = -1
NOT SUFFICIENT
Combining the two statements
Only common solution is {x} = -2 hence
SUFFICIENT
Answer: Option C
06 Jun 2023, 21:43
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rheam25
The two statements are contradictory. If \(x^2 ≤ 4\) then \(-2 <= x < 0\) (since \(x\) is negative) but statement 1 says that \(x <= -2.5\) which is impossible. Because of that, there is no meaning when combining the statements so the answer should be E.
