Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 1912:30 PM EST
-01:30 PM EST
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more
Nov 1811:00 AM PST
-12:00 PM PST
Join us in a live GMAT practice session and solve 30 challenging GMAT questions with other test takers in timed conditions, covering GMAT Quant, Data Sufficiency, Data Insights, Reading Comprehension, and Critical Reasoning questions.
Nov 2001:30 PM EST
-02:30 PM IST
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2407:00 PM PST
-08:00 PM PST
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
08 Apr 2024, 08:09
Kudos
Bookmarks
Dropdown 1: A
Dropdown 2: 12.5
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
69% (02:37) correct
31%
(02:46)
wrong
based on 684
sessions
History
Date
Time
Result
Not Attempted Yet
%20at%20six%20locations%20(1).png)
The graph above shows rainfall (in mm) for May, June, and July 2022 at six locations (A to F).
Based on the graph above, June accounts for the majority of the total rainfall over the three months at location , and the rainfall at that location in June represents percent of the total rainfall across all six locations for that month.
Attachment:
Rainfall(in mm) at six locations (1).png [ 16.9 KiB | Viewed 6904 times ]
ShowHide Answer
Official Answer
Dropdown 1: A
Dropdown 2: 12.5
27 Jan 2025, 03:13
Kudos
Bookmarks
Bunuel
Official Solution:
Drop-down 1:
Majority means more than 50%. To identify the location where June accounts for the majority of the rainfall, look for the location with a blue column longer than the combined lengths of the other two columns. At location A, the blue column is 100 mm, while the other two columns (May and July) are 25 mm and 50 mm, respectively. Since 100 mm is greater than the combined total of 75 mm, location A meets the criterion.
Drop-down 2:
Next, calculate the percentage of location A's rainfall in June relative to the total rainfall across all six locations in June. Add the lengths of the blue columns for all six locations, which total 800 mm. Location A's rainfall in June is 100 mm, so 100/800 = 12.5%. Therefore, location A's rainfall in June represents 12.5% of the total rainfall across all six locations in June.
Correct answer:
Dropdown 1: "A"
Dropdown 2: "12.5"
30 Jan 2025, 20:10
Kudos
Bookmarks
1. Let's calculate the percentage of rainfall in each location that comes from June and see which are greater than 50% (which is majority).
- Location A. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{100}{25 + 100 + 50} \approx 0.571 = 57.1\% > 50\%\).
- Location B. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{150}{75 + 150 + 75} = 0.5 = 50\% = 50\%\).
- Location C. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{75}{100 + 75 + 150} \approx 0.231 = 23.1\% < 50\%\).
- Location D. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{125}{100 + 125 + 75} \approx 0.417 = 41.7\% < 50\%\).
- Location E. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{150}{100 + 150 + 75} \approx 0.462 = 46.2\% < 50\%\).
- Location F. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{200}{50 + 200 + 175} \approx 0.471 = 47.1\% < 50\%\).
Location A works.
2. In total, the amount of rain that came in June is equal to 100 + 150 + 75 + 125 + 150 + 200 = 800. The percentage of that which comes from location A is \(\frac{100}{800} = 12.5\%\).
3. Our answer will be: D1 - A and D2 - 12.5.
- Location A. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{100}{25 + 100 + 50} \approx 0.571 = 57.1\% > 50\%\).
- Location B. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{150}{75 + 150 + 75} = 0.5 = 50\% = 50\%\).
- Location C. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{75}{100 + 75 + 150} \approx 0.231 = 23.1\% < 50\%\).
- Location D. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{125}{100 + 125 + 75} \approx 0.417 = 41.7\% < 50\%\).
- Location E. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{150}{100 + 150 + 75} \approx 0.462 = 46.2\% < 50\%\).
- Location F. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{200}{50 + 200 + 175} \approx 0.471 = 47.1\% < 50\%\).
Location A works.
2. In total, the amount of rain that came in June is equal to 100 + 150 + 75 + 125 + 150 + 200 = 800. The percentage of that which comes from location A is \(\frac{100}{800} = 12.5\%\).
3. Our answer will be: D1 - A and D2 - 12.5.
