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The least of five consecutive odd integers is \(x - 3\). What is the greatest of five integers?
(A) \( x + 3 \)
(B) \(x\)
(C) \(x+5\)
(D) \( x+7\)
(E) \( x+9 \)
(A) \( x + 3 \)
(B) \(x\)
(C) \(x+5\)
(D) \( x+7\)
(E) \( x+9 \)
11 Jan 2022, 07:57
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harish1986
The least of five consecutive odd integers is \(x - 3\). What is the greatest of five integers?
(A) \( x + 3 \)
(B) \(x\)
(C) \(x+5\)
(D) \( x+7\)
(E) \( x+9 \)
(A) \( x + 3 \)
(B) \(x\)
(C) \(x+5\)
(D) \( x+7\)
(E) \( x+9 \)
Consecutive odd integers increase by 2 .
For example: 5, 7, 9, 11, 13, 15.....
The smallest (1st) odd integer = x - 3
So, the next (2nd) odd integer = (x - 3) + 2 = x - 1
The 3rd odd integer = (x - 1) + 2 = x + 1
The 4th odd integer = (x + 1) + 2 = x + 3
The 5th (greatest) odd integer = (x + 3) + 2 = x + 5
Answer: C
General Discussion
17 Jan 2022, 11:25
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I think the quickest way here is to use numbers.
For simplicity take first 5 odd integers : 1, 3, 5, 7, 9
The least is equal to x-3
===> x-3 = 1
x = 4
Now the largest odd integer is 9, so find x in terms of 9:
x + 5 = 9
==> C
For simplicity take first 5 odd integers : 1, 3, 5, 7, 9
The least is equal to x-3
===> x-3 = 1
x = 4
Now the largest odd integer is 9, so find x in terms of 9:
x + 5 = 9
==> C
