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13 Sep 2019, 10:43
Kudos
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
67% (02:46) correct
33%
(02:30)
wrong
based on 67
sessions
History
Date
Time
Result
Not Attempted Yet
The length and breadth of a courtyard are 20m and 10m respectively. Square-shaped tiles of 2m length of different colors are used to pave the courtyard. Black tiles are laid along all the sides as the first row. If green tiles are laid in one-third of the remaining area and yellow tiles are laid in the rest of the area, then how many yellow tiles are required?
(A) 12
(B) 16
(C) 24
(D) 32
(E) 40
(A) 12
(B) 16
(C) 24
(D) 32
(E) 40
13 Sep 2019, 19:34
Kudos
Bookmarks
Hovkial
Total Area = 20*10=200 units
Area of one tile = 2*2=4 units..
Number of tiles in entire room = \(\frac{200}{4}=50\)...(a)
Now along the border, number of tiles that can be put \((\frac{20}{2}+\frac{10}{2})*2-4=26\).....(a)
-4, because the corner tiles at 4 vertices is counted twice.
Therefore remaining tiles =(a)-(b)=50-26=24..
Now \(\frac{1}{3}\) of it is covered with green tiles and, therefore, the remaining \(\frac{2}{3}*24\) or 16 tiles by Yellow tiles
B
14 Sep 2019, 03:52
Kudos
Bookmarks
Hovkial
Area of the Courtyard = 20 m * 10 m=200 sq. mts.
Area of one tile = 2 m * 2 m = 4 sq. mts.
Therefore, the number of tiles to be paved = 200 / 4 = 50 tiles
Also, on each "longer" side, there are 10 tiles and on each "wider" side, there are 5 tiles.
now black tiles are along all sides as first row.
So total black tiles = 10 + 10 + 3 (exclude the ones already taken for "longer" side) + 3 = 26
So, total tiles left = 50 - 26 = 24
Out of these, 1/3 are green. So, 2/3 are yellow.
So, (2/3)*24 = 16 tiles are Yellow.
Ans = B
