Let length of each side of square A be 10

Area of A = 10^2 = 100

Since , length of each side of square A is increased by 100 percent to make square B

length of each side of square B = 2*10 = 20

Area of B = 20^2 = 400

Since , length of the side of square B is increased by 50 percent to make square C

length of each side of square C= 1.5*20 = 30

Area of C= 30^2 = 900

Difference in areas of C and cummulative areas of A and B = 900 -(400+100) = 400

percent is the area of square C greater than the sum of the areas of squares A and B = (400/500) * 100 % = 80%

Answer B

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