RatneshS wrote:

Vyshak wrote:

Total number of ways of selecting the local orchestra = 6C2 * 5C1 * 8C4

Number of ways of selecting the orchestra by having both Suzette and Monica = 6C2 * 5C1 * 6C2

Number of ways of selecting the orchestra such that Suzette and Monica are not together = 6C2 * 5C1 (8C4 - 6C2) = 75 * 55 = 4125

Answer: A

Hi

Please tell the difference between yours and mine approach

6C2.5C1(6C4 + 2C1.7C3)

Hi,

In your approach you have selected either Suzette or Monica (2C1) which is fine. However you have chosen 7 members(7C3) when there are only 6 members remaining, resulting in a wrong answer. 2C1 * 6C3 should provide you the correct answer.

In your approach the correct answer should be read as: 6C2.5C1(6C4 + 2C1.6C3)