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The number 571+572+573 can be expressed as the products of 3
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Updated on: 25 Mar 2014, 01:08
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The number 571+572+573 can be expressed as the products of 3 consecutive integers. What is the sum of these 3 consecutive integers? A. 32 B. 33 C. 34 D. 35 E. 36
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Originally posted by tinashine20 on 26 Nov 2012, 04:03.
Last edited by Bunuel on 25 Mar 2014, 01:08, edited 1 time in total.
Added the OA.




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Re: The number 571+572+573 cab be expressed
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26 Nov 2012, 04:19




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Re: The number 571+572+573 can be expressed as the products of 3
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19 Dec 2012, 23:37
tinashine20 wrote: The number 571+572+573 can be expressed as the products of 3 consecutive integers. What is the sum of these 3 consecutive integers?
A. 32 B. 33 C. 34 D. 35 E. 36 \(=571+572+573=1716=(13)(11)(2)(2)(3)\) after seeing 11 and 13, I knew the third should be 12 without calculating rem. factors.\(=11+12+13= 36\) Answer: E
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Re: The number 571+572+573 can be expressed as the products of 3
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25 Mar 2014, 00:46
Addition of any 3 consecutive numbers is always divisible by 3
So, options A, C , D are ruled outNow focus on options 33 & 36 It can be either 10, 11, 12 (Gives zero at the end after multiplication; ignore this series) or 11, 12, 13 (Matches fine) Answer = E
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Re: The number 571+572+573 can be expressed as the products of 3
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24 Dec 2014, 05:33
571+572+573 = 1716 = 2*2*3*11*13 = 12*11*13
11+12+13 = 36



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Re: The number 571+572+573 can be expressed as the products of 3
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24 Dec 2014, 23:05
571 + 572 + 573 can be written as 572 1 + 572 + 572 + 1 = 3*572 = 3 * 4 * 11 * 13 = 11 * 12 * 13... Ans. E



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Re: The product of three consecutive integers is equal to 571+572+573.
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19 Sep 2017, 23:27
petrified17 wrote: :roll: The product of three consecutive integers is equal to 571+572+573. What is the sum of thoseconsecutive integers?
A) 32 B) 33 C) 34 D) 35 E) 36 \(571+572+573 = 1716\) Now, \(1716 = 11*12*13\) So \(11+12+13=36\) Option \(E\)



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Re: The product of three consecutive integers is equal to 571+572+573.
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19 Sep 2017, 23:29
niks18 wrote: petrified17 wrote: :roll: The product of three consecutive integers is equal to 571+572+573. What is the sum of thoseconsecutive integers?
A) 32 B) 33 C) 34 D) 35 E) 36 \(571+572+573 = 1716\) Now, \(1716 = 11*12*13\) So \(11+12+13=36\) Option \(E\) how did you derive 11*12*13 from 1716?



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Re: The product of three consecutive integers is equal to 571+572+573.
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19 Sep 2017, 23:42
petrified17 wrote: niks18 wrote: petrified17 wrote: :roll: The product of three consecutive integers is equal to 571+572+573. What is the sum of thoseconsecutive integers?
A) 32 B) 33 C) 34 D) 35 E) 36 \(571+572+573 = 1716\) Now, \(1716 = 11*12*13\) So \(11+12+13=36\) Option \(E\) how did you derive 11*12*13 from 1716? Hi petrified17Factorize 1716, you will get 2*2*3*11*13. so it is evident that the three consecutive numbers has to be 11, 12 & 13



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Re: The number 571+572+573 can be expressed as the products of 3
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20 Sep 2017, 02:01
Another method is to note that the sum of these three will end in 6. If product of 3 consecutive integers ends in 6, the units digits of integers would be either 1, 2, 3 or 6, 7, 8. The units digit of sum of the units digits 1, 2, 3 would be 6 giving only possible answer 36. The units digit of sum of the units digits 6, 7, 8 would be 1 which is not there in the options. Posted from my mobile device
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The number 571+572+573 can be expressed as the products of 3
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03 Dec 2018, 21:23
tinashine20 wrote: The number 571+572+573 can be expressed as the products of 3 consecutive integers. What is the sum of these 3 consecutive integers?
A. 32 B. 33 C. 34 D. 35 E. 36 Another approach: Sum of 3 consecutive integers is 3n + 3. Subtracting 3 from each of the answer choices, we can eliminate A, C, D as they will not be divisible by 3. We are left with B and E. B) 33 = 3n + 3 => n = 10 E) 36 = 3n + 3 => n = 11 Since the sum of 571, 572 and 573 gives a unit digit of 6, n cannot be 10 so we can eliminate answer choice B. We are left with answer choice E.




The number 571+572+573 can be expressed as the products of 3 &nbs
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