chetan2u wrote:

The numerator of a fraction is multiple of two numbers. One of the numbers is greater than the other by 2. If the greater number is smaller than the

denominator by 4, what will be the minimum value of the fraction ?

(1) -1

(2) \(\frac{-1}{5}\)

(3) 0

(4) \(\frac{1}{5}\)

(5) 1

source - formatting, adding OA and reposting Q from other subforum

let the denominator be x, therefore the numerator will be (x-4)(x-6)

fraction = \(\frac{(x-4)(x-6)}{x}\)

what does (x-4)(x-6) tell you1) It tells us that x<4 and x>6, both terms will be negative and the value will be positive.

2) At 4 and 6 it will be 0

3) AND at x as 5, the value will be NEGATIVE

so lowest value will be at x = 5\(\frac{(x-4)(x-6)}{x}=\frac{(5-4)(5-6)}{5}=\frac{-1}{5}\)

B

If I let x = -1 in the equation from the quoted solution, then the constructed fraction works out to -35, which is smaller than any of the answer choices. Am hoping someone can help me understand my mistake.